Jack is mowing a lawn that has a shed,
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Answer: 160.4040
Step-by-step explanation:
Here , the claim is "The standard deviation of pulse rates of adult males is more than 11 bpm." , i.e.
We use Chi-square test statistic for the test statistic to test the standard deviations :
, where s= sample standard deviation ,
= population standard deviations and n = sample size.
As per given , n=153 , s= 11.3
Then, Required test statistic will be :
Hence, the value of the test statistic. = 160.4040