Hello,
If we want to factor the expression, we have to solve
3x² + 10x + 8 = 0
a = 3 ; b = 10 ; c = 8
∆ = b² - 4ac = 10² - 4 × 3 × 8 = 4 > 0
x1 = (-b - √∆)/2a = (-10 - 2)/6 = -12/6 = -2
x2 = (-b + √∆)/2a = (-10 + 2)/6 = -8/6 = -4/3
Factor :
a (x - x1)(x - x2)
= 3(x + 2)(x + 4/3)
= (x + 2)(3x + 4)
Pee brain. . .you get it okay
Answer:
its 8, so insert to forms of 8!!! so a and c!
Step-by-step explanation:
Problem 1 Answer: x = 2/3y+8
Show Work:
Step 1: Add 2y to both sides.
3x−2y+2y=24+2y
3x=2y+24
Step 2: Divide both sides by 3.
3x/3 = 2y+24/3
x = 2/3y+8
Problem 2 Answer: x=−2y+48
Show Work:
Add -2y to both sides.
x+2y+−2y=48+−2y
x=−2y+48
