All categories

3 years ago

Using the equation y=kx and the table below, find the constant of proportionality (k).

Mathematics

2 answers:

iogann1982 [59]3 years ago

8 0

Answer:

k = 9/4

Step-by-step explanation:

Here , we have given equation and we need to find k.

To find k, we have given equation which is y = kx

pick any point from the table and substitute in the equation.

y = kx

We choose :- x = 8 and y = 18

18 = 8 × k

Divide each side by 8

18/8 = k

9 / 4 = k

elena-s [515]3 years ago

4 0

Answer:

k = 9/4

Step-by-step explanation:

To find k, use the equation

y = kx

Pick a point

72 = k *32

Divide each side by 32

72/32 = k

9/4 = k

You might be interested in

A local hardware business wishes to find out how many of the local residents would use a delivery service. They call every tenth

Free_Kalibri [48]

It is systematic because they are going every tenth person, in a random manner.

7 0

4 years ago

Graph y = 4x + 2 where is it grqphed at

cestrela7 [59]

Starting point: (0, 2) and can go to (1, 6).
This shows the slope and y-intercept. Hope this helps.

5 0

3 years ago

Help please quickly!!!!1!

Sindrei [870]

there is no question here

5 0

3 years ago

Read 2 more answers

What is the assoicative property of 10+(a+b)

Scilla [17]

Associative property means to change the grouping so you would have to change the parenthesis.
(10+a)+b
The order has to stay the same!

4 0

3 years ago

Question part points submissions used use newton's method with the specified initial approximation x1 to find x3, the third appr

serious [3.7K]

Set $f(x)=2x^3-3x^2+2$ . Find the tangent line $\ell_1(x)$ to $f(x)$ at the point when $x=x_1$ :

$f'(x)=6x^2-6x\implies f'(x_1)=12$ (slope of $\ell_1$ )

$\implies\ell_1(x)=12(x-x_1)+f(x_1)=12(x+1)-3=12x+9$

Set $x_2=-\dfrac9{12}$ , the root of $\ell_1(x)$ . The tangent line $\ell_2(x)$ to $f(x)$ at $x=x_2$ has slope and thus equation

$f'(x_2)=\dfrac{63}8\implies\ell_2(x)=\dfrac{63}8\left(x+\dfrac9{12}\right)-\dfrac{17}{32}=7x+\dfrac{151}{32}$

which has its root at $x_3=-\dfrac{151}{224}\approx-0.6741$ .

(The actual value of this root is about -0.6777)

5 0

3 years ago