Answer both questions please
1 answer:
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is the linear equation to find the temperature T at an elevation x on the mountain, where x is in thousands of feet.
<em><u>Solution:</u></em>
The linear equation in slope intercept form is given as:
T = cx + k ------ (i)
Where "t" is the temperature at an elevation x
And x is in thousands of feet
<em><u>Given that its 76 degrees fahrenheit at the 6000-foot level of a mountain</u></em>
Given, when c = 6 thousand ft and fahrenheit
This implies,
From (i)
76 = c(6) + k
76 = 6c + k
⇒ k = 76 - 6c ----- (ii)
<em><u>Given that 49 degrees Fahrenheit at the 12000-foot level of the mountain</u></em>
Given, when c = 12 thousand ft and fahrenheit
This implies,
From (i)
49 = c(12) + k
49 = 12c + k
Substitute (ii) in above equation
49 = 12c + (76 - 6c)
49 = 12c + 76 - 6c
49 - 76 = 6c
6c = -27
Substituting the value of c in (ii) we get
Substituting the value of c and k in (i)
Where "x" is in thousands of feet
Thus the required linear equation is found
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S =
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer