Answer:
The Sum Of The Integers From -6 To 58 is <u>1690.</u>
Step-by-step explanation:
Given,


We have to find out the sum of integers from -6 To 58.
Firstly we will find out the total number of terms that is 'n'.
Here 

Now we use the formula of A.P.

On substituting the values, we get;

So there are 65 terms in between -6 To 58.
That means we have to find the sum of 65 terms in between -6 To 58.
Now we use the formula of Sum of n_terms.

On substituting the values, we get;

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>
The answer is d) none because substituting -1/4x + 5/3 for y in the first equation gives 3x - 3x + 5/3 = 20 so 5/3 = 20 which is not true.
For the first one, the answer is 2. You can only fold it vertically and horizontally. For the second one, the answer is O because any way you turn it, it still looks like O. I hope this helps!
Answer:
3/2 or 1 1/2
Step-by-step explanation:
5÷3 1/3
5/1 ÷ 10/3 because you have to get it into an improper fraction form in order to divide
5/1 × 3/10 because you have to multiply the first number by the reciprocal
5 and 10 cancel out so you would have 2 at the bottom
3/2 or 1 1/2
X is Kevin; Y is Dan
X = 3Y
X - 4 = 5(Y - 4)
3Y - 4 = 5(Y - 4)
3Y - 4 = 5Y - 20
+ 4 +4
4 cancels each other out.
3Y = 5Y - 16
- 5 -5
5 cancels each other out.
-2Y = -16
/2 /2
Y = 8
X = 3Y;
X = 3 x 8;
Thus,
X = 24;
Kevin(x) is 24