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3 years ago

Sarah backstrokes at an average speed of 8 meters/second and swims for 250 seconds, how far did she swim?

Mathematics

1 answer:

garri49 [273]3 years ago

5 0

Answer:

2000 meters in 250 seconds

Step-by-step explanation:

250*8

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PQR is a right angled triangle with angle R 90 According to Pythagoras rule

vazorg [7]

Answer:

The Pythagorean Theorem states that $a^2+b^2=c^2$

Step-by-step explanation:

This formula applies to the side lengths and means that the length of leg "a" squared, plus the length of leg "b" squared, will equal the length of hypotenuse "c" squared. Please state a more specific question so I can go into more detail if you need it :)

3 0

3 years ago

If a triangle has side lengths 5 cm, 18 cm, and 12 cm, is it a right triangle?

Dimas [21]

Answer:

No, it's not a right triangle.

Step-by-step explanation:

1. The Pythagorean Theorem states that the area of the square whose side is the hypotenuse (longest side of a right triangle) is equal to the sum of the area of the squares from the two other sides.

2. The longest side in this "triangle" has 18 centimeters, and the other 2 sides are 5 and 12 centimeters.

3. Let's apply the Pythagorean Theorem to see if 5^2 + 12^2 = 18^2

$5^2 + 12^2 = 18^2$
$25 + 144 = 324$
$169 \neq 324$

4. Okay, so the sum of the area of the squares from the two other sides is not equal to the hypotenuse squared, therefore, it's not a right triangle.

(Plus, it's not even a triangle because 7 < x < 17, and the third "side", 18, is not between 7 and 17.)

5 0

3 years ago

A local art studio offers a new session of drawing classes every 12 days. A competing art studio offers a new session of drawing

Artist 52 [7]

To solve this we are going to find the least common multiple of 8 and 12.
Remember that the least common multiple (LCM) of tow or more numbers is the smallest positive number that is multiple of those two or more numbers.
To find our LCM we are going to list the multiples of 8 and 12, and then, we are going to select the first common number in those lists:

Multiples of 8: 8,16,24,32,40,....
Multiples of 12: 12,24,36,48,...

Notice that the first common value between the two list is 24, and that is precisely the number of days it will take for drawing sessions to coincide.

We can conclude that after 24 days both art studios will start a new drawing session on the same day.

5 0

3 years ago

Can someone plz help me with this one problem plz!!! I WILL MARK BRAINLIEST!!!

Digiron [165]

Answer:

(1,6) , (2,7) , (3,8) , (4,9) , (5,10)

Step-by-step explanation:

Given equation: y = x + 5

when x = 1, y = 1 + 5 = 6

(1,6)

when x = 2, y = 7

(2,7)

when x = 3 , y = 8

(3,8)

when x = 4 , y = 9

(4,9)

when x = 5 , y = 10

(5,10)

4 0

3 years ago

If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"

seraphim [82]

Answer:

$a + b + c = \pi \\ = > c= \pi - a - b \\ < = > \tan(c) = \tan(\pi - a - b) = -\tan(a + b)$

Step-by-step explanation:

we have:

$\tan(a) + \tan(b) + \tan(c) \\ = \tan(a) + \tan(b) - \tan(a + b) \\ = \tan( a) + \tan(b) - \frac{ \tan(a) + \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{ ( \tan(a) + \tan(b) ) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (1)$

we also have:

$\tan(a) \tan(b) \tan(c) \\ = - \tan(a) \tan(b) \tan(a + b) \\ = \frac{ -(\tan( a ) + \tan(b) ) \tan(a) \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{( \tan(a) + \tan(b)) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (2)$

from (1)(2) => proven

5 0

3 years ago