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ziro4ka [17]
3 years ago
14

Jerome Anthony are reading the same book drumhedz already read 46 pages in feet and additional 7 page per night Cindy has read 2

8 pages every 20 mm equation 2 (46 + 7n)=28 to determine how many nights n, it will take for sydney to have read twice as many pages as jerome​
Mathematics
1 answer:
german3 years ago
7 0

Answer:yo

Step-by-step explanation:

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3. Terdapat dua bidang saling berpotongan dan tidak berhimpitan maka
yanalaym [24]

Kelas : VII (1 SMP)

Materi : Geometri

Kata Kunci : Garis, Sisi, Rusuk, Bidang

Pembahasan :

Titik adalah bentuk yang paling dasar dalam geometri. Titik ditulis dengan tanda titik dan diberi nama dengan huruf besar. Sebuah titik hanya untuk menunjukkan posisi dan memiliki ukuran nol (panjang nol, lebar nol, dan tinggi nol).

Garis adalah kumpulan titik-titik yang memanjang secara tak berhingga ke dua arah. Sebuah garis memiliki panjang tidak terbatas.

Ruas garis adalah potongan sebuah garis. Sebuah ruas garis memiliki dua titik ujung dan diberi nama menurut kedua titik ujungnya.

Sinar garis merupakan bagian dari sebuah garis, namun hanya memiliki satu titik ujung. Sebuah sinar garis diberi nama dengan huruf titik ujungnya dan titik lain pada sinar garis tersebut.

Sudut adalah dua sinar yang memiliki titik ujung yang sama.

Titik ujung tersebut dinamakan titik sudut dan sinar-sinar garisnya dinamakan sisi-sisi sudut. 

Bidang adalah kumpulan titik yang jumlahnya tak terhingga yang membentuk permukaan rata yang melebar ke segala arah sampai tak terhingga. Sebuah bidang memiliki panjang tak terbatas, lebar tak terbatas, dan tinggi nol. Sebuah bidang biasanya digambarkan dengan gambar segi empat dan diberi nama dengan satu huruf besar.

Rusuk adalah suatu garis yang merupakan pertemuan dari dua sisi bidang.

Dua bidang berpotongan bila terdapat garis persekutuan atau garis potong antara kedua bidang tersebut.

Dua bidang sejajar bila antara kedua bidang tersebut tidak memiliki garis persekutuan.

Dua bidang berhimpit bila setiap titik terletak pada kedua bidang tersebut.

Mari kita lihat soal tersebut.

Jika dua bidang saling berpotongan dan tidak berhimpitan, maka perpotongannya berbentuk garis.

Jadi, jawabannya adalah B.

Semangat!

4 0
3 years ago
I need help I don't understand how to do this
murzikaleks [220]
What is the problem? Is there isn't a problem, do you just what help for a test?
6 0
4 years ago
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Show how to use distributive property to rewrite and find (32x6)+(32x4)
Anna35 [415]
320 is the answer to this question
5 0
3 years ago
Which expression is equivalent to x + y + x + y + 3(y + 5)?
Lemur [1.5K]

Answer:

2x + 5y + 15

Step-by-step explanation:

Step 1: Combine like terms

2x + 2y + 3(y + 5)

Step 2: Distribute

2x + 2y + 3y + 15

Step 3: Combine like terms

2x + 5y + 15

8 0
3 years ago
The​ quality-control manager at a compact fluorescent light bulb​ (CFL) factory needs to determine whether the mean life of a la
Illusion [34]

Answer:

a) Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 7539

b) t=\frac{7359-7539}{\frac{840}{\sqrt{49}}}=-1.5    

The degrees of freedom are given by:

df=n-1=49-1=48  

The p value is given by:

p_v =P(t_{(48)}  

c) 7359-2.01\frac{840}{\sqrt{49}}=7117.8    

7359+2.01\frac{840}{\sqrt{49}}=7600.2    

d) For this case since the confidence interval contains the value of 7539 we don't have enough evidence to reject the null hypothesis at the significance level given of 5%. same conclusion using the hypothesis test and with the confidence interval

Step-by-step explanation:

Part a and b

Data given

\bar X=7359 represent the sample mean

\sigma=840 represent the population standard deviation

n=49 sample size  

\mu_o =7539 represent the value to test

t would represent the statistic  

p_v represent the p value

Hypothesis to verify

We want to verify if the mean life is different from 7539 hours, the system of hypothesis would be:  

Null hypothesis:\mu \geq 7539  

Alternative hypothesis:\mu < 7539  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{7359-7539}{\frac{840}{\sqrt{49}}}=-1.5    

The degrees of freedom are given by:

df=n-1=49-1=48  

The p value is given by:

p_v =P(t_{(48)}  

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 7539

Part c

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

We can find the critical value using the confidence level given of 95% and using the t distribution with 48 degrees of freedom we got t_{\alpha/2}=\pm 2.01

Now we have everything in order to replace into formula (1):

7359-2.01\frac{840}{\sqrt{49}}=7117.8    

7359+2.01\frac{840}{\sqrt{49}}=7600.2    

Part d

For this case since the confidence interval contains the value of 7539 we don't have enough evidence to reject the null hypothesis at the significance level given of 5%. same conclusion using the hypothesis test and with the confidence interval

3 0
3 years ago
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