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Karo-lina-s [1.5K]
3 years ago
13

I need help I don't understand how to do this

Mathematics
2 answers:
murzikaleks [220]3 years ago
6 0
What is the problem? Is there isn't a problem, do you just what help for a test?
Cloud [144]3 years ago
5 0
On this you are really just trying to find the lowest number that both of the numbers go into. For example if you have the numbers 6 and 9, 18 would be the lowest common multiple because it is the smallest number that both the numbers go into. An example with fractions is 3/4 and 5/6, what they are trying to tell you is that you find a common denominator for the two fractions (here it would be 12, making them 9/12 and 10/12) and then you can add them together to get the least common multiple (for this problem it would be 19/12). This is a faster way that works for fractions, but would not work as well in my opinion for whole numbers.
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Find the distance between the points given.<br><br>(-3, 2) and (9, -3)​
klemol [59]

Answer:

Distance = 13

Step-by-step explanation:

Using the distance formula, plug in the two points:

d = sqrt(9-(-3))^2+(-3-2)^2

d = sqrt(12)^2+(-5)^2

d = sqrt144+25

d = sqrt169

d = 13

6 0
3 years ago
Answer each question and explain your reasoning.
SVETLANKA909090 [29]

Answer:

1. 30 mins

Step-by-step explanation:

5 0
2 years ago
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DedPeter [7]

Answer:

its between c or b

Step-by-step explanation:

I've done this test before

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3 years ago
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Steven investigates the amount of damage to the head gaskets on the trucks in his fleet and finds that the damage index depends
pshichka [43]

answer- it is D because.2/3 is decrease.

8 0
3 years ago
Which piece of additional information can be used to prove △CEA ~ △CDB?
Slav-nsk [51]

<u>Answer-</u>

<em>The correct answer is</em>

<em>∠BDC and ∠AED are right angles</em>

<u>Solution-</u>

In the ΔCEA and ΔCDB,

m\angle BCD=m\angle ACE

As this common to both of the triangle.

If ∠BDC and ∠AED are right angles, then m\angle E=90=m\angle D

Now as

∠BCD = ∠ACE and ∠BDC = ∠AED,

∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)

Then, ΔCEA ≈ ΔCDB

Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.


5 0
3 years ago
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