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3 years ago

PLEASE HELPPPP THE DROP DOWN MENUES ARE ALL THE SAME

Mathematics

1 answer:

White raven [17]3 years ago

6 0

Answer:

a) distributive property

b) combining like terms

c) commutative property of addition

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A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In

lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

P.Q. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of males having blood disorder= $\frac{250}{1000}$ = 0.25

$\hat p_2$ = sample proportion of females having blood disorder = $\frac{275}{1000}$ = 0.275

$n_1$ = sample of males = 1000

$n_2$ = sample of females = 1000

$p_1$ = population proportion of males having blood disorder

$p_2$ = population proportion of females having blood disorder

Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.

So, 95% confidence interval for the difference between the population proportions, ( $p_1-p_2$ ) is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ${(\hat p_1-\hat p_2)-(p_1-p_2)}$ < $1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

P( $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ( $p_1-p_2$ ) < $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

95% confidence interval for ( $p_1-p_2$ ) =

[ $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ , $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ]

= [ $(0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ , $(0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ ]

= [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0

3 years ago

Mary throws her Grandma’s favorite crystal dish out the second floor window, which is 6 meters from the ground. She is really up

wlad13 [49]

we know that

acceleration due to gravity is 9.8m/s^2

so, we get

$a(t)=9.8$

and acceleration will always be constant

we know that

integral of acceleration is velocity

so, we can integrate both sides

$\int \:a\left(t\right)dt=\int \:9.8dt$

$v(t)=9.8t+C$

we are given

v(0)=35m/s

we can use it and find C

$v(0)=9.8*0+C$

$35=9.8*0+C$

$C=35$

now, we can plug it back

$v(t)=9.8t+35$

we know that

integral of velocity is height

we can integrate it again

$\int \:v\left(t\right)dt=\int \:\left(9.8t+35\right)dt$

$s(t)=\int \:\left(9.8t+35\right)dt$

$s(t)=4.9t^2+35t+C$

now, we have

s(0)=6

we can use it and find C

$s(0)=4.9(0)^2+35(0)+C$

$6=4.9(0)^2+35(0)+C$

now, we can plug back C

$C=6$

and we get

$s(t)=4.9t^2+35t+6$ .............Answer

4 0

3 years ago

Read 2 more answers

Y=x^2 translate 4 units down and 3 units left

klasskru [66]

Answer: Hello! When a graph is translated 4 units down you are moving all of the y values. This makes it the easiest translation that we do, other than no translation! All you have to do is subtract 4. Your equation is y=x2 - 4. If you wanted to move the graph up it is addition and if you want to move it down it is subtraction. When you translate right to left it is more complicated! Hope this helps. :))

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2 years ago

2) n-1 - 9n can you simplify

Morgarella [4.7K]

-1 - 10n is a simple version

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3 years ago

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What is the value of R?

Vinil7 [7]

Answer:

Step-by-step explanation: