a 20 of of ice at 0c is dropped into water at boiling point, specific heat capacity of water =4200 J/kg•c, sepesific latent heat
1 answer:
Answer:
15 KJ
Explanation:
The quantity of heat (Q) required is given as:
Q = mcΔθ + mL
where m is the mass of ice, c is its specific heat capacity, L is its specific latent heat andΔθ is the change in temperature.
Given: m = 20g, temperature of ice = 0, specific heat capacity of water = 4200 J/kg
, latent heat of fusion of ice = 3.3 x 10^(5) J/kg, temperature of water = 100
.
Q = m (cΔθ + L)
= 0.02(4200 x (100) + 330000)
= 0.02(420000 + 330000)
= 0.02 (750000)
Q = 15000
Q = 15000 Joules
Q = 15KJ
The quantity of heat needed to complete the conversion is 15 KJ.
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