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Mazyrski [523]
3 years ago
9

According to the Law of Reflection, the angle of incidence the angle of reflection. O A. is greater than B. is less than C. equa

ls D. is opposite from​
Physics
1 answer:
Amanda [17]3 years ago
8 0

Answer:

C. Equals

Explanation:

Law of reflection Equals the angle of incidence

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An object is dropped near the earth's surface. At the end of 4.0 s, how fast is it falling in m/s? (Ignore air resistance.)
Sati [7]
For free falling bodies, the final velocity may be calculated through the equation,
                                   Vf = gt
Where g is the acceleration due to gravity (9.8 m/s²) and t is the time elapsed. Substituting the known values,
                                   Vf = (9.8 m/s²) x (4 s) = 39.2 m/s
Therefore, the object's velocity is approximately 39.2 m/s. 
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3 years ago
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If the current in a wire of a cd player is 12.0 ma, how long would it take for 6.50 c of charge to pass a point in this wire? an
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The current intensity is defined as the amount of charge Q that passes through a certain point of an electrical wire in a time interval of \Delta t:
I= \frac{Q}{\Delta t}

In our problem, the current intensity is
I=12.0 mA=0.012 A
while the amount of charge that passes a certain point of the wire is 
Q=6.50 C

If we re-arrange the previous equation:
\Delta t= \frac{Q}{I}
we can find the time needed for this amount of charge to pass through a point of the wire:
\Delta t= \frac{6.50 C}{0.012 A} =541.7 s
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3 years ago
Charges of +5C and −9C are at a distance of 1m from each other. Which diagram represents the force between the two charges?
weqwewe [10]

the answer is CCCCCCCCCCCCCCCCC

8 0
3 years ago
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We drive at a speed of 20 km/h for 3 hours. Then we drive 4 hours at 30 km/h. Calculate our average speed.
Afina-wow [57]

First speed = 20km/h

Time = 3 hours

Distance = 3×20

<h3> = <u>60 km</u></h3>

Second speed = 30km/h

Time = 4 hours

Distance = 4×30

<h3> = <u>120 km</u></h3>

Total distance = 60+120 = <u>180km</u>

Total time = 3+4 =<u> 7 hours</u>

Average speed = 180/7

<h3> = <u>25.71</u><u> </u><u>km</u><u>/</u><u>h</u></h3>

Hope this will help...

4 0
3 years ago
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A 5.0-kilogram sphere, starting from rest, falls freely 22 meters in 3.0 seconds near the surface of a planet. Compared to the a
Whitepunk [10]

Answer:

C) one-half as great

Explanation:

We can calculate the acceleration of gravity in that planet, using the following kinematic equation:

\Delta x=v_0t+\frac{gt^2}{2}

In this case, the sphere starts from rest, so v_0=0. Replacing the given values and solving for g':

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The acceleration due to gravity near Earth's surface is g=9.8\frac{m}{s^2}. So, the acceleration due to gravity near the surface of the planet is approximately one-half of the acceleration due to gravity near Earth's surface.

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3 years ago
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