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3 years ago

How is amplitude and frequency connected?

2 answers:

8 0

They are connected because, Amplitude is the climax of the wave. Frequency is the number of the waves that passes at a particular instant. If you were at the beach, the frequency is how regular a wave bumps you. And amplitude is the climax of the waves that crashed you.

Alexxandr [17]3 years ago

3 0

Amplitude is tge distance between the two top point of a full wave (crest to crest) frequency is # of vibrations/waves per second, the more vibs per second, the smaller amplitude, and the opposite

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The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 10.6 V and b = -4.90 V/m. (a) Determine the pote

cestrela7 [59]

Answer:

a) 10.6V

b) E = 4.9V/m, +x direction

c) E = 4.9V/m, +x direction

Explanation:

You have the following function:

$V=a+bx$ (1)

for the potential in a region between x=0 and x=6.00 m

a = 10.6 V

b = -4.90V/m

$V=10.6V-4.90\frac{V}{m}x$

a) for x=0 you obtain for V:

$V=10.6V-4.90\frac{V}{m}(0m)=10.6V$

b) The relation between the potential difference and the electric field can be written as:

$E=-\frac{dV}{dx}=-b=-(-4.9V/m)=4.9V/m$ (2)

the direction is +x

c) The electric field is the same for any value of x between x=0 and x=6m.

Hence,

E = 4.9V/m, +x direction

6 0

4 years ago

For a given velocity of projection in a projectile motion, the maximum horizontal distance is possible only at ө = 45°. Substant

Scilla [17]

Consider the projectile launched at initial velocity V at angle θ relative to the horizontal.
Neglect wind or aerodynamic resistance.

The initial vertical velocity is Vsinθ.
When the projectile reaches its maximum height of h, its vertical velocity will be zero.
If the time taken to attain maximum height is t, then
0 = Vsinθ - gt
t = (Vsinθ)/g, where g = acceleration due to gravity.

The horizontal component of launch velocity is Vcosθ. This velocity remains constant because aerodynamic resistance is ignored.
The time to travel the horizontal distance D is twice the value of t.
Therefore
D = Vcosθ*[(2Vsinθ)/g]
= (2V²sinθ cosθ)/g
= (V²sin2θ)/g

In order for D (horizontal distance) to be maximum, $\frac{dD}{d \theta} =0$
That is,
$\frac{2V^{2}}{g} cos(2 \theta )=0$

Because $\frac{2V^{2}}{g} \neq 0$ , therefore cos(2θ) = 0.
This is true when 2θ = π/2 => θ = π/4.

It has been shown that the maximum horizontal traveled can be attained when the launch angle is π/4 radians, or 45°.

4 0

4 years ago

In which reaction are the atoms of elements rearranged?

NNADVOKAT [17]

Answer:

D. Hydrogen combines with oxygen to form water.

Explanation:

Hydrogen combining with oxygen to form water is a typical example of chemical reaction.

During a chemical reaction, atoms of elements are rearranged. Most chemical reactions obey the law of conservation of mass which states that "matter is neither created nor destroyed in a chemical reaction but atoms are simply rearranged".

The other choices given are nuclear reactions. In such reactions, atoms are not rearranged but are simply destroyed and made in the process.

4 0

3 years ago

a cube of iron was heated to 70C and transferred to a beaker containing 100g of water at 20c the final temperature of the water

garri49 [273]

Complete question:

a cube of iron was heated to 70C and transferred to a beaker containing 100g of water at 20c the final temperature of the water and the iron was 23c what are the heat capacity of iron and water ?

Answer:

The heat capacity of iron which is equal to heat capacity of water is 1254 J.

Explanation:

Given;

initial temperature of the iron, t₁ = 70 °C

mass of water, m₂ = 100 g

initial temperature of water, t₂ = 20 °C

final temperature of the mixture, t = 23 °C

The heat lost by iron = heat gained by water

Thus, the heat capacity of iron = heat capacity of water

Heat gained by water is given by;

Q = mcΔθ

Q = mc(t - t₂)

where;

c is the specific heat capacity of water = 4.18 J/g°C

Q = (100 )(4.18)(23 - 20)

Q = 1254 J

Therefore, the heat capacity of iron which is equal to heat capacity of water is 1254 J.

5 0

3 years ago

The International Space Station (ISS) orbits Earth at an altitude of 4.08 × 105 m above the surface of the planet. At what veloc

alukav5142 [94]

This question involves the concepts of orbital velocity and orbital radius.

The orbital velocity of ISS must be "7660.25 m/s".

The orbital velocity of the ISS can be given by the following formula:

$v=\sqrt{\frac{GM}{R}}$

where,

v = orbital velocity = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = Mass of Earth = 5.97 x 10²⁴ kg

R = orbital radius = radius of earth + altitude = 63.78 x 10⁵ m + 4.08 x 10⁵ m

R = 67.86 x 10⁵ m

Therefore,

$v=\sqrt{\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}{67.86\ x\ 10^5\ m}}$

Learn more about orbital velocity here:

brainly.com/question/541239

3 0

2 years ago