Answer:
Option D.
A fan is turned from high speed to low speed.
Explanation:
It is important to note that air is also a fluid.
In a system, static pressure of air increases with the speed of rotation of the fan. This is because when the speed of the fan is increased, the force with which it is pushing the air molecules is increased. Since pressure is a relationship between force and area, the pressure of the air molecules will be increased.
Conversely, when the speed of the fan is reduced, the priming force on the air molecules will be reduced, hence the pressure of the air will drop.
This makes option D the correct option
Answer:
A) 17.7 m/s
B) 15.98 m
C) Zero
E) 9.8 m/s²
Explanation:
given information
distance, h = - 34 m
time, t = 5 s
A) What is the initial speed of the egg?
h - h₀ = v₀t - t², h₀ = 0
- 34 = v₀ 5 - \frac{1}{2} 9.8 5²
- 34 = 5 v₀ - 122.5
v₀ = 122.5 - 34/5
= 17.7 m/s
B) How high does it rise above its starting point?
v² = v₀² - 2gh
v = 0 (highest point)
2gh = v₀²
h = v₀²/2g
= 17.7²/2 (9.8)
= 15.98 m
C) What is the magnitude of its velocity at the highest point?
v = 0 (at highest point)
E) What are the magnitude and direction of its acceleration at the highest point?
g= 9.8 m/s², since the egg is moved vertically, the acceleration is the same as the gravitational acceleration.
Given: Heat given to mercury (Q) = 100 J
Mass of mercury (m) = 80 g = 80 × 10⁻³ kg
Specific Heat capacity of mercury (c) = 138 J/kg°C
Let the rise of temperature be Δt
Formula Used: Q = mcΔt
Here, all alphabets are in their usual meanings.
Calculation:
Q = mcΔt
or, Δt = Q / mc
or, Δt = 100 J /[(80 × 10⁻³ kg)×(138 J/kg°C)]
or, Δt = 9.058 °C
or, Δt = 9.1 °C
Hence, the required increase in temperature will be 9.1 °C.
Answer:
SUPONIENDO QUE NO HAY FRICCIÓN
Explanation:
F = 66 kg() = 132 N