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tamaranim1 [39]
3 years ago
14

Which planets are gas giants

Chemistry
1 answer:
Amiraneli [1.4K]3 years ago
4 0

Answer:

INNER PLANTS

Mercury - Rocky planets

Venus - Rocky planets

Earth - Rocky planets

Mars - Rocky plants

------------------------------------

OUTER PLANETS

Jupiter - gas giants

Saturn - gas giants

Uranus - gas giants

Neptune - gas giants

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Which is true of electric cars?
lianna [129]

Answer:

they produce no DIRECT emissions

Explanation:

that is why they are good in cities to reduce air pollution . but sometypes can produce lesser emissions.

3 0
3 years ago
What would happen to the volume of the container if the pressure is increased by a factor of 2​
telo118 [61]

Answer:

volume of the container will decreases if pressure increases.

Explanation:

According to Boyle's law:

Pressure is inversely proportional to volume which means if pressure of a gas increases the volume of the gas will decreases as gas molecules will collide and come closer forcefully so volume will decreases. And its formula for determining volume and pressure is:

<em>PV=nRT</em>

where "R" is a ideal gas constant

"T" is temperature and

"n" is number of particles given in moles while "V" is volume and "P" is pressure.

8 0
3 years ago
The ideal gas constant, R has several different values that could be used. Which quantity causes these differences?
Vera_Pavlovna [14]

Answer:

The answer is A

Explanation:

6 0
2 years ago
The standard heats of formation for CO2(g), C2H6(g), and H2O(l) are -394.0 kJ/mol, -84.00 kJ/mol, and -286.0 kJ, respectively. W
Ivanshal [37]

Answer:

ΔH°r = -1562 kJ

Explanation:

Let's consider the following combustion.

C₂H₆(g) + 7/2 O₂(g) ⇒ 2 CO₂(g) + 3 H₂O(l)

We can calculate the standard heat of reaction (ΔH°r) using the following expression:

ΔH°r = ∑np × ΔH°f(p) - ∑nr × ΔH°f(r)

where,

ni are the moles of reactants and products

ΔH°f(i) are the standard heats of formation of reactants and products

The standard heat of formation of simple substances in their most stable state is zero. That means that ΔH°f(O₂(g)) = 0

ΔH°r = ∑np × ΔH°f(p) - ∑nr × ΔH°f(r)

ΔH°r = [2 mol × ΔH°f(CO₂) + 3 mol × ΔH°f(H₂O)] - [1 mol × ΔH°f(C₂H₆) + 7/2 mol × ΔH°f(O₂)]

ΔH°r = [2 mol × (-394.0 kJ/mol) + 3 mol × (-286.0 kJ/mol)] - [1 mol × (-84.00 kJ/mol) + 7/2 mol × 0]

ΔH°r = -1562 kJ

6 0
3 years ago
64.0 grams of Sulfur Dioxide absorbed 5.00 kJ of heat and immediately evaporated.
Airida [17]

Answer:

ewqdf

Explanation:

edfeagfefwas

ag

8 0
3 years ago
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