Density = Mass/Volume
d = .254/129.4
Answer:
5.59x10^-3 moles
Explanation:
The balanced equation for the reaction is given below:
HCl + KOH —> KCl + H2O
Now we can obtain the number of mole of HCl required to produce 5.59x10^-3 moles of KCl as follow:
From the balanced equation above, 1 mole of HCl produced 1 mole of KCl.
Therefore, 5.59x10^-3 moles of HCl will also produce 5.59x10^-3 moles of KCl.
From the illustration made above, we can see evidently that 5.59x10^-3 moles of HCl is required to produce 5.59x10^-3 moles of KCl
O1Fl2
1. Assume an 100g sample, so the percentage will stay the same
2. Covert each element into their molar mass
29.6/16.00=1.8 mols of O
70.4/19.00=3.7 mols of Fl
3. Divide both by the smallest value of mol
1.8/1.8=1 O
3.7/1.8=2 Fl
4. Write the empirical formula:
O1Fl2
Answer:
for the balanced equation
