2 years ago

What is the value of the expression below 1/4 = 8? (5.NF.7)

Mathematics

1 answer:

alexgriva [62]2 years ago

8 0

The answer would be 1/32

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2 years ago

ASAP need help please

Akimi4 [234]

Answer:

A or B

Step-by-step explanation:

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please help me evaluate this. the answer is B but im not sure how to get the answer without using a calculator. please show step

iragen [17]

Answer:

b. 9/100

Step-by-step explanation:

It helps if you have memorized the cubes of small integers. Of course, the ones needed here are ...

3³ = 27

10³ = 1000

The desired value can be simplified to ...

$\left(-\dfrac{1000}{27}\right)^{-2/3}=\left(-\sqrt[3]{\dfrac{3^3}{10^3}}\right)^2=\dfrac{(-3)^2}{10^2}=\dfrac{9}{100}$

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2 years ago

Find Dy/dX when x^y×y^x=1

victus00 [196]

by dy/dx, we'll be assuming that "y" is encapsulating a function, a function in terms of "x".

$x^y\cdot y^x=1\implies \stackrel{\textit{\large product rule}}{\stackrel{\textit{chain rule}}{yx^{y-1}(1)}\cdot y^x+x^y\cdot \stackrel{\textit{chain rule}}{xy^{x-1}\cdot \frac{dy}{dx}}}~~ = ~~0 \\\\\\ y^{1+x}x^{y-1}+x^{y+1}y^{x-1}\cdot \cfrac{dy}{dx}=0\implies \cfrac{dy}{dx}=\cfrac{-y^{1+x}x^{y-1}}{x^{y+1}y^{x-1}} \\\\\\ \cfrac{dy}{dx}=-~~ y^{(1+x)-(x-1)}~~x^{(y-1)-(y+1)} \\\\\\ \cfrac{dy}{dx}=-~~ y^2x^{-2}\implies \cfrac{dy}{dx}=\cfrac{-y^2}{x^2}$

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1 year ago

Help please<br> I will give a brainliest

andreyandreev [35.5K]

The other person is correct the answer is C

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2 years ago