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2 years ago

6

Can somebody please answer this asap

2 answers:

erastovalidia [21]2 years ago

5 0

Answer:

you have to add all of them up it will get you some of your awner

Maru [420]2 years ago

4 0

Answer:

add

Step-by-step explanation:

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9 Questions/45 points

Finger [1]

You have a lot of questions here, try breaking them up into multiple posts and you may get more responses.

I will help with some.

<span>(x+3)=0

The solution is just -3.
-----------------------------------------------------------------
3m(m-4)=0

The two solutions are 0 and 4.
-----------------------------------------------------------------
(r-3)(r+2)=0

The two solutions are and 3 and -2.
</span>
I hope this gets you started in the right direction.

3 0

3 years ago

Add 4xly, -2xy?, -5xy?, 312y <br>step by step explanation plzz

storchak [24]

Answer:

8xy that is the answer...................

8 0

3 years ago

Can someone pls help me with this?

Lisa [10]

Answer: A

Step-by-step explanation: 3(1)+k =8 8-3=5

5 0

3 years ago

Read 2 more answers

On a coordinate plane, 2 lines are shown. Line A B has points (negative 4, negative 2) and (4, 4). Line C D has points (0, negat

klasskru [66]

Answer:

Option A) They are parallel because their slopes are equal.

Step-by-step explanation:

We are given the following in the question:

Line AB:

(-4, -2), (4,4)

Line CD:

(0,-3), (4,0)

Formula to calculate slope =

$(x_1, y_1), (x_2, y_2)\\\\\\text{Slope} = m = \dfrac{y_2 - y_1}{x_2 - x_1}$

Slope of AB =

$(-4, -2), (4,4)\\\\m_{AB} = \dfrac{4-(-2)}{4-(-4)} = \dfrac{6}{8} = \dfrac{3}{4}$

Slope of CD =

$(0,-3), (4,0)\\\\m_{CD} = \dfrac{0-(-3)}{4-0} = \dfrac{3}{4}$

Thus,

$m_{AB} = m_{CD}$

Thus, the two lines are parallel.

Option A) They are parallel because their slopes are equal.

3 0

3 years ago

Read 2 more answers

fire work a travels at the speed 300 ft/s firework b travels 240 ft/s. firework b is launched 0.25s before firework a. how many

storchak [24]

Answer:

Both fireworks will explode after 1 seconds after firework b launches.

Step-by-step explanation:

Given:

Speed of fire work A= 300 ft/s

Speed of Firework B=240 ft/s

Time before which fire work b is launched =0.25s

To Find:

How many seconds after firework b launches will both fireworks explode=?

Solution:

Let t be the time(seconds) after which both the fireworks explode.

By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation

Firework A= 330(t)

Firework B=240(t)+240(0.25)

Since we need to know the same time after which they explode, we can equate both the equations

330(t) = 240(t)+240(0.25)

300(t)= 240(t)+60

300(t)-240(t)= 60

60(t)=60

$t=\frac{60}{60}$

t=1

7 0

3 years ago