Simplify. 9y-2y Hehhe can someone help me

Given: f(x)=x^2, g(x)=x+6, h(x)=7 Find h{g[f(x)]}

arsen [322]

Step-by-step explanation:

$f(x)=x^2,\ g(x)=x+6,\ h(x)=7\\\\h(x)=7\ \text{It's the constant function. Therefore}\ h\{g[f(x)]\}=7$

4 0

3 years ago

1/3(15y-6) I need help plz!!!

Rufina [12.5K]

Answer:

(4.99y-1.99); rounded it would be (5y-2)

Step-by-step explanation:

Distribute 1/3 into the parentheses, since you can't subtract 15y-6 because they don't have the same variable.

5 0

3 years ago

Evaluate the integral Integral ∫ from (1,2,3 ) to (5, 7,-2 ) y dx + x dy + 4 dz by finding parametric equations for the line seg

n200080 [17]

$\vec F(x,y,z)=y\,\vec\imath+x\,\vec\jmath+3\,\vec k$

is conservative if there is a scalar function $f(x,y,z)$ such that $\nabla f=\vec F$ . This would require

$\dfrac{\partial f}{\partial x}=y$

$\dfrac{\partial f}{\partial y}=x$

$\dfrac{\partial f}{\partial z}=3$

(or perhaps the last partial derivative should be 4 to match up with the integral?)

From these equations we find

$f(x,y,z)=xy+g(y,z)$

$\dfrac{\partial f}{\partial y}=x=x+\dfrac{\partial g}{\partial y}\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$f(x,y,z)=xy+h(z)$

$\dfrac{\partial f}{\partial z}=3=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=3z+C$

$f(x,y,z)=xy+3z+C$

so $\vec F$ is indeed conservative, and the gradient theorem (a.k.a. fundamental theorem of calculus for line integrals) applies. The value of the line integral depends only the endpoints:

$\displaystyle\int_{(1,2,3)}^{(5,7,-2)}y\,\mathrm dx+x\,\mathrm dy+3\,\mathrm dz=\int_{(1,2,3)}^{(5,7,-2)}\nabla f(x,y,z)\cdot\mathrm d\vec r$

$=f(5,7,-2)-f(1,2,3)=\boxed{18}$

8 0

3 years ago

Question 3 1 pts 2 and -2 are 4 units apart on the number line. True False

EastWind [94]

It’s actually true!

^ ^ ^ ^
<—|——|——|——|——|—>
-2 -1 0 1 2

The 4 arrows above the number line represents the distance between 2 and -2 which is 4!

4 0

3 years ago

Point P is the center of dilation. Triangle A B C is dilated to create triangle A prime B prime C prime. The length of P A is 2

Orlov [11]

Answer:

C. No, it is not a dilation because the points of the image are not moved away from the center of dilation proportionally.

Step-by-step explanation:

Dilation is the process in which the size i.e dimensions of a given figure is either increased or decreased by a scale factor, without changing the shape of the figure.

Given that: PA = 2, PB = 3, A $A^{I}$ = 4, B $B^{I}$ = 5.

So that: P $A^{I}$ = 6, P $B^{I}$ = 8.

Therefore, triangle A'B'C' is not an exact dilation of triangle ABC. So that the correct option is; No, it is not a dilation because the points of the image are not moved away from the center of dilation proportionally.

5 0

3 years ago

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