The answer is 75 and here's why.
Let's figure out the amount of remaining votes to prove this.
250 total votes - 150 votes for candidate a = 100 votes.
minus ↑ sign
Candidate B received 25% of the votes, so let's find<u> 25% of 100</u>
<u>100 * 0.25 = 25 votes</u>
Candidate B only got 25 votes (that's kinda sad, poor guy)
<u>100 - 25 votes = the # of votes candidate C got </u>
Candidate C got 75 votes!
Answer:
y= -3/4x+2
Step-by-step explanation:
3x+4y=8
-3x -3x
----------------
4y=-3x+8
Divided by 4 on each sides
y= -3/4x+2
Answer:
363
Step-by-step explanation:
Formula for area of a circle
A = πr^2
Where r = radius
The circle has a given radius of 11
To find the area of the circle we simply substitute r in the formula with the value of the radius (11)
( Also note that the question says to use 3 for π )
A = πr^2
π = 3
r = 11
Substitute values in formula
A = (3)(11)^2
11^2 = 121
A = 121(3)
121(3) = 363
A = 363
Answer: 49
and im a taurus
Step-by-step explanation:
Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
