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devlian [24]
3 years ago
9

Select all the values for that indicate r a positive slope for the line of best fit.

Mathematics
1 answer:
Whitepunk [10]3 years ago
8 0

Answer:

u didn't show anything so I can't help u. can u show a picture or something

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Which is greater 5/8 or 5/12?
ElenaW [278]
5/8 is greater than 5/12
5 0
3 years ago
Read 2 more answers
A survey of a group’s viewing habits over the last year revealed the following
Tom [10]

Answer:

0.52

Step-by-step explanation:

The computation of the percentage of the group in which none of the three sports watched is shown below:

= gymnastic percentage + baseball percentage + soccer percentage - gymnastic & baseball percentage - baseball & soccer percentage - gymnastic & soccer percentage + three sports percentage

= 0.28 + 0.29 + 0.19 - 0.14 - 0.12 - 0.18 + 0.08

= 0.48

Now the percentage is

= 1 - 0.48

= 0.52

7 0
3 years ago
How is the graph of y = |x| − 1 different from the parent function f(x) = |x|?
Jlenok [28]

Answer:

Step-by-step explanation:

the graph moves down one unit

if you add/subtract outside the parent function the graph moves up/down

3 0
3 years ago
Find all values of x in the interval [0, 2π] that satisfy the equation. <br><br>6sin²(x) = 3
34kurt

Answer:

The solutions are π/4, 3π/4,5π/4,7π/4

Step-by-step explanation:

The given equation is

6sin²(x) = 3

Divide by 6 to get:

{ \sin}^{2} (x) =  \frac{1}{2}

This implies that;

\sin(x) = \pm  \frac{ \sqrt{2} }{2}

If

\sin(x) = \frac{ \sqrt{2} }{2}

x =  \frac{\pi}{4}

in the first quadrant

x =  \frac{3\pi}{4}

in the second quadrant.

If

\sin(x) = -  \frac{ \sqrt{2} }{2}

x =  \frac{5\pi}{4}

in the third quadrant

x =  \frac{7\pi}{4}

5 0
3 years ago
Find the value of x and the length of both chords if BW=2x+10, WD=4, CW=7x+5, and WE=2.
daser333 [38]

Answer:

The value of x is 5

The lengths of the chords are 24 units and 42 units

Step-by-step explanation:

In a circle if two chords intersected at a point inside it there are four segments created, two in each cord, the products of the lengths of the line segments on each chord are equal

∵ BD and CE are two chords in a circle intersected at W

∴ The two segments of chord BD are BW and WD

∴ The two segments of chord CE are CW and WE

- By using the rule above

∴ BW × WD = CW × WE

∵ BW = 2x + 10 and WD = 4

∵ CW = 7x + 5 and WE = 2

- Substitute them in the rule above

∴ (2x + 10) × 4 = (7x + 5) × 2

∴ 4(2x) + 4(10) = 2(7x) + 2(5)

∴ 8x + 40 = 14x + 10

- Subtract 14x from both sides

∴ - 6x + 40 = 10

- Subtract 40 from both sides

∴ - 6x = - 30

- Divide both sides by - 6

∴ x = 5

∵ Chord BD = 2x + 10 + 4

∴ Chord BD = 2x + 14

- Substitute the value of x to find its length

∴ Chord BD = 2(5) + 14 = 10 + 14

∴ Chord BD = 24 units

∵ Chord CE = 7x + 5 + 2

∴ Chord CE = 7x + 7

- Substitute the value of x to find its length

∴ Chord CE = 7(5) + 7 = 35 + 7

∴ Chord CE = 42 units

5 0
3 years ago
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