Ask question

Ask question

All categories

3 years ago

5

PLEASE HELP ASAP!!!!!Sunny earns $22.75 per week delivering newspapers. He worked as a delivery boy for 3 weeks. He also earned

$32.75 last
month doing chores around the house. He spent $14.25 of his total earnings to download music on his mobile device. Sunny put
of the remaining money in his savings account. Sunny used the following steps to find the total money he put in his savings
5
account:
Step 1: [($22.75 + 3) + $32.75 - $14.25)
5
Step 2: [$44.25)
Step 3: $11.0625
In which step did Sunny first make an error? Use words to explain how Sunny can correct his error.

1 answer:

alexandr1967 [171]3 years ago

4 0

Answer:

error in step one

Step-by-step explanation:

Sunny earns $22.75 per week delivering. delivery boy for 3 weeks.

That means $22.75 x 3 not $22.75 + 3

He can correct his mistake by doing this:

<em>Step 1: [($22.75 * 3) + $32.75 - $14.25] * 1/ 5 </em>

<em> </em>

<em>Step 2: [$86.75] *1/5 </em>

<em> </em>

<em>Step 3: $17.35</em>

<em />

<em> </em>

<em> </em>

You might be interested in

Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

The area of a room is 600 square feet. The length is (x + 5) feet and the width is (x + 4) feet. Find the dimensions of the room

tangare [24]

I'm going to assume that the room is a rectangle.

The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle.

You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:
$A = lw\\
600 = (x+5)(x+4)\\
600 = x^{2} + 9x + 20
$

Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:
$600 = x^{2} + 9x + 20\\
x^{2} + 9x - 580 = 0\\
(x + 29)(x - 20) = 0\\
x + 29 = 0, \:\: x - 20 = 0\\
x = -29, x = 20$

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.

The dimensions of your room are 25ft (length) by 24ft (width).

8 0

3 years ago

Read 2 more answers

A right rectangular prism is packed with cubes of side length 1/2 inch. If the prism is packed with 5 cubes along the length, 3

lesya [120]

The answer is C 11 1/4 or 11.25 Cubic inches

6 0

3 years ago

Please some one help me.

vagabundo [1.1K]

Answer:

-11

Step-by-step explanation:

You need to take the absolute value of 12-15 which would be 3. Then take -8-3 which would be -11

3 0

3 years ago

On a coordinate plane, a curved line crosses the y-axis at (0, 1), crosses the x-axis at (.25, 0), turns at point (2, negative 3

Artyom0805 [142]

Answer:

All real numbers greater than or equal to -3

Step-by-step explanation:

we know that

The curved line could be a vertical parabola opening upwards with vertex at (2,-3)

The vertex is a minimum

The y-intercept is the point (0,1)

The x-intercepts are the points (0.25,0) and (3.75,0)

so

The domain is the interval -----> (-∞,∞)

All real numbers

The range is the interval ----> [-3,∞)

All real numbers greater than or equal to -3

6 0

2 years ago

Read 2 more answers