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2 years ago

8

What is the value of the function at x=-2

1 answer:

disa [49]2 years ago

3 0

Answer: i think the correct answer is a

Step-by-step explanation: so if x=-2 then that would mean y=-4 because 2 and 4 r equivalent so it has to be a

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Solve the system by substitution.<br> y = 8x<br> y = 10x - 4<br> Submit Answer

erik [133]

Answer:

x=1, y=8

Step-by-step explanation:

Plug y=8x into y=10x-4.

8x=10x-4

Subtract 10x from each side.

-2x=-2

Divide each side by -2.

x=1

Plug x=1 into y=8x.

y=8(1)

y=8

5 0

3 years ago

If Eli showed a 8.9% ROI on his $8000.00 investment, how much was his return on his investment

telo118 [61]

8.9% is equal to 0.089 because a percent is over a 100. So, you can just multiply the ROI by the investment to get:

$0.089(8000) = 712$

Your answer is: $712.

6 0

2 years ago

Read 2 more answers

EM Company produces two types of laptop computer bags. The regular version requires $32 in capital and 4 hours of labor and sell

expeople1 [14]

Answer:

Step-by-step explanation:

Given that EM company produces two types of laptop computer bags.

Let regular version produced be R and deluxe version be D

Total capital required

= $32R+38D\leq 2100$

Total labor hours required

= $4R+6D\leq 280$

Sales revenue = $46R+55D$

Solving the two constraints we have

10D $\leq$ 140

D can be atmost 14 and hence R can be 49

Otherwise if D is made 0, R = 65 maximum

If R is made 0, D maximum is 46

Thus corner points are (65,0) (0.,46) or (49,14)

Sales revenue for (65,0) = 2990

(0,46) is 2530

(49,14) is 3024

Maximum when R =14 and D is 49

5 0

3 years ago

It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

3 years ago

. Which graph has f(x) = 1xI as its parent function?

Blababa [14]

Answer: Im not sure

Step-by-step explanation:

you didnt list/provide the graphs for me to answer. :I

6 0

1 year ago