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Ksivusya [100]
3 years ago
8

Alright, I am getting annoying at this point but who can help me with this one?

Mathematics
1 answer:
amm18123 years ago
7 0

Answer:

A

Step-by-step explanation:

F(x) = 4x^2 + 1

G(x) = x^2 - 5

(F-G)(x) = (4x^2+1 - x^2-5)

collect like terms

(F-G)(x) = (4x^2-x^2 + 1-5)

= (3x^2 - 4)

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If the parabola has y = -4 at both x = 2 and x = 3, then since a parabola is symmetric, its axis of symmetry must be between x = 2 and x = 3, or at x = 5/2. Our general equation can then be:
y = a(x - 5/2)^2 + k
Substitute (1, -2): -2 = a(-3/2)^2 + k
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Substitute (2, -4): -4 = a(-1/2)^2 + k
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3 years ago
Solve for a<br><br> 3a+2&gt; 3a-6/3
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Answer:

a>-2

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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