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3 years ago

Find the reciprocal of -1 1/12

Mathematics

2 answers:

Sauron [17]3 years ago

7 0

1 12/1 is the answer

polet [3.4K]3 years ago

5 0

Answer:

-12/13

Step-by-step explanation:

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How can you use rates to compare the cost of two cereal boxes that are different sizes.

Anarel [89]

You subtract and devide i beleve. hope iu helped sorry if wrong.

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3 years ago

In a fruit cocktail, for every 15 ml of orange juice you need 5 ml of apple juice and 50 ml of coconut milk. What is the ratio o

Kruka [31]

Answer:

1/14:5/7:3/14

Step-by-step explanation:

Since orange=15

Apple=5

Coconut milk=50

50+15+5

Orange=15/70

Divide both by 5

=3/14

Apple=5/70

Divide both by 5

=1/14

Coconut milk=50/70

Divide both by 10

=5/7

So the ratio of apple to coconut to orange

1/14:5/7:3/14

8 0

3 years ago

Say that you leave montevideo at 6:20 p.m. on sunday to fly to jerusalem. when you arrive in jerusalem, the local time is 10:00

iragen [17]

Its A. Five hours ahead :)

6 0

3 years ago

Read 2 more answers

Help please..........

Paha777 [63]

1. Arc KL = 23
2. Arc LON = 203
3. Arc OM = 113
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5. 157

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5 0

3 years ago

A 555-mile, 5-hour plane trip was flown at two speeds. For the first part of the trip, the average speed was 105 mph. Then the t

Pepsi [2]

Answer:

Hence Distance traveled at speed 115 mph is 345 miles and Distance traveled at speed 105 mph is 210 miles.

Step-by-step explanation:

Given:

Total Distance = 555 mile

Total time = 5 hour

Let time taken to travel at 115 mph be t

So Time taken to travel at 105 mph will be equal to difference between Total time and time taken to travel at 115 mph.

Time taken to travel at 105 mph = $5-t$

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 115 mph = $115t$

Also;

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 105 mph = $105(t-5) = 105t - 525$

Now Total Distance traveled is equal sum of Distance traveled in 115 mph and Distance traveled in speed 105 mph

$115t-(105t-525)=555\\\\115t-105t+525=555\\\\10t+525=555\\\\10t=555-525\\\\10t=30\\\\t=\frac{30}{10}=3$

Time taken to travel at 115 mph = 3 hrs.

Time taken to travel at 105 mph = $5-t=5-3=2\ hrs$

Now Distance traveled in 115 mph = $115t = 115 \times 3 = 345\ miles$

Distance traveled in 105 mph = $105(5-t) = 105(5-3)= 105\times 2 = 210\ miles$

Hence Distance traveled at speed 115 mph is 345 miles and Distance traveled at speed 105 mph is 210 miles.

6 0

3 years ago