Question

A woman does 236 J of work

Answer 1

Answer:

The woman's force was directed 59.22⁰ to the horizontal.

Explanation:

Given;

work done by the woman, W = 236 J

distance through the load was moved, d = 24.4 m

applied force, F = 18.9 N

inclination of the force, = θ

The work done by the woman is calculated as;

W = Fdcosθ

$cos \ \theta = \frac{W}{Fd} \\\\cos \ \theta = \frac{236 }{18.9 \times 24.4} \\\\cos \ \theta = 0.5118\\\\\theta = cos^{-1} ( 0.5118)\\\\\theta =59.22^0$

Therefore, the woman's force was directed 59.22⁰ to the horizontal.