Energy is conserved. If the ball reaches a height of 5.50 m, it has gained a certain amount of gravitational potential energy. That energy had to come from somewhere. From this fact, you can deduce the speed of the ball at the end of the impact with the racket.
<h3>What is
gravitational potential energy?</h3>
Gravitational energy or gravitational potential energy is the potential energy a huge item has corresponding to one more monstrous article because of gravity. It is the potential energy related with the gravitational field, which is delivered (changed over into active energy) when the articles fall towards one another. Gravitational potential energy increments when two articles are brought further apart. It is the potential energy related with the gravitational field, which is delivered (changed over into dynamic energy) when the items fall towards one another. Gravitational potential energy increments when two items are brought further separated.
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The pressure of the water on the diver is given in an expression written as:
<span>p=15+15/33d
where p is the pressure and d is the distance of the diver </span><span>below the surface.
The pressure is calculated as follows:
</span>p=15+15/33(100) = 15.00 pounds per square feet
Therefore, the correct answer is option A.
1) v = gt = 10*1.5 = 15 m/s
2) r = gt^2 /2 = 10*(1.5)^2 / 2 = 11.25 meters
Answer:
2.5 m/s^2
Explanation:
the formula for acceleration (or the one you use in this case) is a=vf-vi/t
where vf is equal to final velocity, vi is equal to initial velocity, and t is equal to time.
vf= 25 m/s
vi= 0m/s
t=10s 25-0=25, 25/10=2.5 therefore it is 2.5m/s^2
You said 0.5 · m · v² = m · g · h
Divide each side by 'm' : 0.5 · v² = g · h
Multiply each side by 2 : v² = 2 · g · h
Square root each side : v = √(2 · g · h)
You said that g = 9.8 m/s² and h = 875 units
So v = √(9.8 m/s² · 875 units)
v = √(8,575 m·unit/s²)
v = 92.6 / s² · √(m · unit)
