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aliina [53]
3 years ago
12

a ball weighing 100 n is shown suspended from a system of cords. what is the tension in the horizontal and angled cords at 50 de

grees and 90 degrees
Physics
1 answer:
Ymorist [56]3 years ago
6 0
First, we know that the ball is not in motion, so the acceleration is 0

T45 = Fg/sin45  = 100N/sin 45   = 141 N

Thor = T45 cos 45 = 141 N cos45

= 100 N

hope this helps
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An air-plane has an effective wing surface area of 17.0 m² that is generating the lift force. In level flight the air speed over
Lady bird [3.3K]

Answer:

Explanation:

Given that,

Surface area A= 17m²

The speed at the top v" = 66m/s

Speed beneath is v' =40 m/s

The density of air p =1.29kg/m³

Weight of plane?

Assuming that,

the height difference between the top and bottom of the wind is negligible and we can ignore any change in gravitational potential energy of the fluid.

Using Bernoulli equation

P'+ ½pv'²+ pgh' = P'' + ½pv''² + pgh''

Where

P' is pressure at the bottom in N/m²

P" is pressure at the top in N/m²

v' is velocity at the bottom in m/s

v" is velocity at the top in m/s

Then, Bernoulli equation becomes

P'+ ½pv'² = P'' + ½pv''²

Rearranging

P' — P'' = ½pv"² —½pv'²

P'—P" = ½p ( v"² —v'²)

P'—P" = ½ × 1.29 × (66²-40²)

P'—P" = 1777.62 N/m²

Lift force can be found from

Pressure = force/Area

Force = ∆P ×A

Force = (P' —P")×A

Since we already have (P'—P")

Then, F=W = (P' —P")×A

W = 1777.62 × 17

W = 30,219.54 N

The weight of the plane is 30.22 KN

5 0
3 years ago
Read 2 more answers
It decomposes in a first-order reaction with a rate constant of 14 s–1. how long would it take for an initial concentration of 0
VikaD [51]
The rate constant of a reaction can be computed by the ratio of the changes in the concentration and time take taken for it to decompose. Thus, if the rate constant is given to be 14 M/s, we have 

rate = \frac{-(C_{new} - C_{old})}{t}

where C are the concentration values and t is the time taken for it to decompose.

14 = \frac{-(0.02 - 0.06)}{t}
t = 0.003 s

Thus, it will take 0.003 s for it to decompose.
Answer: 0.003 s

4 0
3 years ago
Based on the TIA/EIA 568-B structured cabling standard, the cabling that runs from the telecommunications closet to each work ar
lana [24]

Answer:

False.

Explanation:

Backbone Cabling: A system of cabling that connects the equipment rooms and telecommunications rooms.

Horizontal Cabling: The system of cabling that connects telecommunications rooms to individual outlets or work areas on the floor.

4 0
3 years ago
A 4.00 m long, massless beam rests horizontally on a support 3.00 m from the left
Rus_ich [418]

If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

Given the data in the question;

  • Length of the massless beam;L = 4.00m
  • Distance of support from the left end; x = 3.00m
  • First mass; m1 = 31.3 kg
  • Distance of beam from  the left end( m₁ is attached to ); x_1 = ?
  • Second mass; m_2 = 61.7 kg
  • Distance of beam from  the right of the support( m₂ is attached to ); x_1 = 0.273m

Now, since it is mentioned that the beam is in static equilibrium, the Net Torque on it about the support must be zero.

Hence, m_1g( x-x_1) = m_2gx_2

we divide both sides by g

m_1( x-x_1) = m_2x_2

Next, we make x_1, the subject of the formula

x_1 = x - [ \frac{m_2x_2}{m_1} ]

We substitute in our given values

x_1 = 3.00m - [ \frac{61.7kg\ * \ 0.273m}{31.3kg} ]

x_1 = 3.00m - 0.538m

x_1 = 2.46m

Therefore, If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

Learn more; brainly.com/question/3882839

6 0
3 years ago
A metal block has a mass of 5 grams and a volume of 1 cm3. What is the density of a piece of the same identical metal but with a
Fynjy0 [20]

Answer:

ρ = Mass / Volume     definition of density

ρ  = 5 g / 1cm^3 = 5 g / cm^3

Since the other object is made of the same metal its density is the same:

ρ = 5 g/cm^3

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