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3 years ago

As you approach a roundabout, you should __________________.

Physics

2 answers:

motikmotik3 years ago

8 0

The answer should be B

Alex_Xolod [135]3 years ago

6 0

Answer:

Explanation:

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Explain what happens to a light wave that hits the surface of a pool.

brilliants [131]

A light wave that hits the surface of a pool gets refracted and gives us an apparent image of the surface of the pool, following the concepts of refraction.

<u>Explanation:</u>

Let’s recall the concept of refraction when a light wave passes from medium of rarer to denser. There is a change in the speed of light while travelling from medium of rarer to denser.

There can be a change in the direction as well. This property is known as “Refraction” and the best example to see refraction is watching the surface of a clean pond, lake or pool.

When the light travels from a rarer medium (air) to a denser medium (water), it changes its angle of direction and gets refracted and hit to our eye lenses. With this, we see the surface of the pool at a changed angle and it seems to be a bit shallow than its original depth.

5 0

3 years ago

The ozone the unearths surface from the dangerous radiation. This is an interaction between

Mnenie [13.5K]

The interaction is in the stratosphere.

7 0

3 years ago

. Starting from a stop at a traffic signal, a car speeds up to 20 m/s in 5 seconds. Calculate the acceleration of the car.

Dimas [21]

Answer: 4m/s²

Explanation:

At stop signal car speed iz 0 ; V1=0m/s

After t=5s , car has speed is V2=20m/s

using:

a=(V2-V1)/t

a=(20m/s-0m/s)/5s

a=20m/s/5s

a=4m/s²

4 0

3 years ago

An electron is traveling at 0. 85c. what is its mass? (the rest mass is 9. 11 × 10-31 kg. )

egoroff_w [7]

The mass of the electron is $1.72\times 10^{-30}$ Kg.

<h3>How can we calculate the mass of the electron?</h3>

To calculate the mass of the electron we are using the formula,

$m=\frac{m_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} } } }$

Here we are given,

$m_0$ =The rest mass of an electron = $9. 11 \times 10^{-31}$ kg.

v= The velocity of electron = 0. 85c.

c= The velocity of light = c. (c= $3\times 10^8$ m/s)

We have to found the mass of an electron = m Kg.

Now we substitute the known values, we found that,

$m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-\frac{(0.85c)^{2} }{c^{2} } } }$

Or, $m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-(\frac{0.85c}{c})^2 } }$

Or, $m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-({0.85})^2 } }$

Or, $m=1.72\times 10^{-30}$ Kg.

From the above calculation we can conclude that, The mass of the electron is $1.72\times 10^{-30}$ Kg.

Learn more about electron:

brainly.com/question/860094

#SPJ4

4 0

1 year ago

An object is thrown vertically and has an upward velocity of 18 m/s when it reaches one fourth of its maximum height above its l

Murrr4er [49]

Answer:

v = 25.45 m/s

Explanation:

In order to calculate the initial speed of the object, you take into account the formula for the maximum height reaches by the object. Such a formula is given by:

$h_{max}=\frac{v_o^2}{g}$ (1)

vo: initial speed of the object = 18 m/s

g: gravitational acceleration = 9.8 m/s²

Furthermore you use the following formula for the final speed of the object:

$v^2=v_o^2-2gh$ (2)

h: height

You know that the speed of the object is 18m/s when it reaches one fourth of the maximum height. You use this information, and you replace the equation (1) in to the equation (2), as follow:

$v^2=v_o^2-2g(\frac{h_{max}}{4})=v_o^2-\frac{1}{2}g(\frac{v_o^2}{g})\\\\v^2=v_o^2-\frac{1}{2}v_o^2=\frac{1}{2}v_o^2$

Then, you solve the previous result for vo:

$v_o=\sqrt{2}v=\sqrt{2}(18m/s)=25.45\frac{m}{s}$

The initial speed of the object was 25.45 m/s

3 0

3 years ago