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emmasim [6.3K]
4 years ago
11

Molecules can be made of atoms of the same element only. different elements only. the same or different elements.

Physics
2 answers:
Ira Lisetskai [31]4 years ago
8 0

Both, there are two different types of molecules to distinguish that

Readme [11.4K]4 years ago
3 0

Answer:

the same or different elements.

Explanation:

You might be interested in
Which tools collect images during space exploration? Check all that apply. rovers orbiters satellites space shuttles space stati
grigory [225]

Answer:

1. Rovers- These are vehicles which are designed to move on the surface on any celestial body and collect samples, data and images. Sometimes, these can be used to transport mission crew members.

2. Orbiters- These are spacecrafts designed to orbit any celestial body and collect data in form of images.

3. satellites- artificial satellites are placed in the orbit of celestial bodies for various purposes. There are various types of satellites like communication satellite, weather satellites, space telescopes. These collect images and data inform of signals.

4. space stations: It is a satellite where research and experiments take place. Images are also collected for research purpose.

Space shuttle is a wrong option because it is just a vehicle to transport these satellites and probes into the space and place in the orbit or surface of celestial body.

4 0
4 years ago
Read 2 more answers
A 10.0-kg box is pulled by a horizontal wire in a circle on a rough horizontal surface for which the coefficient of kinetic fric
QveST [7]

Answer:

a)W_{f}=307.87 J

b)W_{f}=615.752 J

c) Therefore it is a nonconservative force

Explanation:

Distance traveled in one complete circular trip against friction  

d=2\pi *r

The force of friction is

F_{f}=u*F_{N}

F_{N}=w*g

The work of friction is the force of friction in the distance so

W_{f}=-F_{f}*d

a).

F_{N}=10kg*9.8\frac{m}{s^2}

F_{N}=98N

F_{f}=0.250*98N

F_{f}=24.5N

W_{f}=-24.5N*2\pi*2m

W_{f}=307.87 J

b).

W_{f}=-24.5N*2\pi*4m

W_{f}=615.752 J

c).

Since the circle returns to its initial position in both cases and the work done by the friction force different in both cases, so the friction force does depend on the path;

3 0
3 years ago
A 620 kg car is traveling at 24 m/s on horizontal ground when it starts up a 30 m high hill. The engine can produce up to 144,00
sweet-ann [11.9K]

Answer:

The kinetic energy of the car at the top of the hill is 140280 Joules.

Explanation:

Mass of the car, m = 620 kg

Speed of the car, v = 24 m/s

Height of the hill, h = 30 m

The engine can produce up to 144,000 J of work during that time, W = 144,000 J

We need to find the kinetic energy of the car at the top of the hill. It can be calculated using conservation of mechanical energy as :

(mgh+K)-\dfrac{1}{2}mv^2=144000

(620\times 9.8\times 30+K)-\dfrac{1}{2}\times 620\times (24)^2=144000

620\times9.8\times30+K=322560

K=140280\ J

So, the kinetic energy of the car at the top of the hill is 140280 Joules. Hence, this is the required solution.

7 0
4 years ago
Which term describes the number of joules used per second by a circuit?
jasenka [17]

Answer:

B) Power

Explanation:

The power is defined by the following equation:

P = W / t

where:

W = work = Force * Distance = [Newton] * [meter]

t = time = seconds

The units for work are give en Newton per second, which is equal to Joules

And for power the unit used commonly is Watts, therefore:

Watts = (Joule/second)

5 0
3 years ago
Read 2 more answers
A 0.51-kg metal sphere oscillates at the end of a vertical spring. As the spring stretches from 0.12 m to 0.23 m (relative to it
den301095 [7]

Answer:

487.23 N/m

Explanation:

Given:

mass of metal sphere 'm'= 0.51kg

the spring stretches from 0.12 m to 0.23 m. Therefore,

s_1}= 0.12m and s_{2}= 0.23m

the speed of the sphere decreases from 6.7 to 3.3 m/s. Therefore,

v_{1}= 6.7m/s and v_2}=3.3m/s

In order to find spring constant, we apply law of conservation of energy. i.e

The change of the kinetic energy of sphere is equal to the change of potential energy of the spring.

So, ΔE_{k} = ΔE_{v}

where,

ΔE_{k} = 1/2 m (v_{1}- v_2})²

ΔE_{v}= 1/2 k (s_1} - s_{2})²

1/2 m (v_{1}- v_2})² = 1/2 k (s_{2}- s_1} )²

k= m [ (v_{1}- v_2})²/(s_{2}- s_1} )²

k= 0.51 [(6.7-3.3)²/ (0.23-0.12)²]

k= 487.23 N/m

Thus, the spring constant of the spring is 487.23 N/m

5 0
4 years ago
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