Please can you help with these math?

Which method would you use to prove that the two triangles are congruent?

Alona [7]

Answer:- AAS postulate

Explanation:-

AAS postulate tells that if two angles and a non-included side of a triangle to equal to the two angles and a non-included side of another triangle then the two triangles are said to be congruent.

Given:- One angle and one side of a triangle is equal to the one angle and one side of the other triangle.

We see there is one more pair of equal angles as they are vertically opposite angles . [See the attachment]

⇒ there is a triangle where two angles and a non-included side of a triangle to equal to the two angles and a non-included side of another triangle then the two triangles are said to be congruent.

⇒ The triangles are congruent [ by ASA postulate]

6 0

3 years ago

Last month, the daily balance in Joana's credit card account was $1,000 for 9 days, $750 for 10 days, $850 for 4 days, and $900

FrozenT [24]

Answer:

$Average = \$873$

Step-by-step explanation:

Given

$1000 for 9 days

$750 for 10 days

$850 for 4 days

$900 for other days

Required

Compute the daily average

First, we need to compute the number of days her balance is $900

Assuming the billing cycle is 30 days;

$Number\ of\ days = 30 - (9 + 10 + 4)$

$Number\ of\ days = 30 - 23$

$Number\ of\ days = 7$

The Average is then calculates using:

$Average = \frac{\sum fx}{x}$

$Average = \frac{1000 * 9 + 750 * 10 + 850 * 4 + 900 * 7}{9 + 10 + 4+ 7}$

$Average = \frac{26200}{30}$

$Average = 873.333333333$

$Average = \$873$ --- Approximated

3 0

3 years ago

Factor the following expression.

mel-nik [20]

Answer:

the factor of 12 is 1 2 3 4 6 12 so that

-3(n+4)

5 0

2 years ago

consider a sequence of independent tosses of a biased coin at times k=0,1,2,…,n. On each toss, the probability of Heads is p, an

omeli [17]

Answer:

1. p*(1-p)

2. n*p*(1-p)

3. p*(1-p)

4. 0

5. p^2*(1-p)^2

6. 57/64

Step-by-step explanation:

1. Let Ik denote the reward (possibly 0) given at time k, for k∈{1,2,…,n}. Find E[Ik].

E[Ik]= p*(1-p)

2. Using the answer to part 1, find E[R].

E[R]= n*p*(1-p)

The variance calculation is more involved because the random variables I1,I2,…,In are not independent. We begin by computing the following values.

3. If k∈{1,2,…,n}, then

E[I2k]= p*(1-p)

4. If k∈{1,2,…,n−1}, then

E[IkIk+1]= 0

5. If k≥1, ℓ≥2, and k+ℓ≤n, then

E[IkIk+ℓ]= p^2*(1-p)^2

6. Using the results above, calculate the numerical value of var(R) assuming that p=3/4, n=10.

var(R)= 57/64

5 0

3 years ago

Lucy went to buy apples, she bought the first two for the full price and the last one for half the price. Is the relationship be

Anit [1.1K]

No it is not proportional. Since she brought the last apple for 1/2 the price, the equation won’t be linear (straight line) anymore so it won’t be proportional. Proportional means the same unit rate.

4 0

3 years ago