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dezoksy [38]
3 years ago
5

Rose’s grandmother is 89 years old. She can knit mittens somewhere between 13 and 16 hours. If she wants to knit 36 mittens for

the students at her church, about how long would it take her? for 15 points
Mathematics
2 answers:
kakasveta [241]3 years ago
5 0
If it takes that long to make one pair, then i’d say maybe 468 hours to make all 36 pairs
Leona [35]3 years ago
5 0
Answer : around 487
( not 100%)


Explanation :
16times 36

Which is equal 576
And the grandmother is 89 so u subtract it and got 487
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kompoz [17]
It is 50,000 less 

450 x 100 = 450,000 
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3 years ago
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Translate this sentence into an equation. 62 is the sum of 12 and Chrissy's age. Use the variable c to represent Chrissy's age.
Greeley [361]
62= 12+c

Which your answer is 50 cause if you take 62 and subtract it to 12 it's 50. So 50 + 12 = 62
5 0
4 years ago
Help pls I attached a picture
seropon [69]

Answer:

x= 7\sqrt{2}

Step-by-step explanation:

It's a 45 45 90 triangle

The legs are = x while the hypotenuse is x \sqrt{2}.

Therefore the answer is 7\sqrt{2}

8 0
3 years ago
Chris has $170.00. Candies cost $8.50 each. How many candies can Chris buy? $<br> Blank
Yuki888 [10]

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20

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8 0
3 years ago
Solve 12^x^2+5x-4 = 12^2x+6
faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

                    12^{x^{2}+5 x-4}=12^{2 x+6}

Since the base on both sides as ‘12’ are the same, we can write it as

                     x^{2}+5 x-4=2 x+6

                     x^{2}+5 x-2 x-4-6=0

                     x^{2}+3 x-10=0

Often, the value of x is easiest to solve by a x^{2}+b x+c=0 by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For a x^{2}+b x+c=0, the values of x which are the solutions of the equation are given by:

                       x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Where, a = 1, b = 3 and c = -10

                       x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}

                       x=\frac{-3 \pm \sqrt{9+40}}{2}

                       x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}

So, the solutions for ‘x’ are

                       x=\frac{-3+7}{2}=\frac{4}{2}=2

                       x=\frac{-3-7}{2}=\frac{-10}{2}=-5

The solutions for ‘x’ are 2 and -5

6 0
3 years ago
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