Answer:
Some of the benefits of sharing a workbook include:
A. Shared information between students (ie: Mary writes a note about (blank) in the workbook and John reads said note and receives addition information about (blank)).
B. ^adding onto this, discussion on interpretations of a passage (ie: John thinks (blank) means this and Mary thinks (blank) means other thing, through notes they can discuss the meaning of the text.
Hope this helps. =)
Answer:
public static void removeInRange(List<Integer> list, int value, int start, int end) {
for (int i = end - 1; i >= start; i--) {
if (list.get(i) == value) {
list.remove(i);
}
}
System.out.println(list);
}
Explanation:
- Create a method named <em>removeInRange</em> that takes four parameters, a list, an integer number, a starting index and an ending index
- Inside the method, initialize a <u>for loop</u> that iterates between starting index and ending index
- If any number between these ranges is equal to the given <em>value</em>, then remove that value from the list, using <u>remove</u> method
- When the loop is done, print the new list
Answer:
(10^6 + 9.9)
Explanation:
Given:
Total number of machine instructions = 1000
Number of page fault in 100 instructions = 1
Number of page faults in 1000 instructions = 10
Time to serve one page fault = 100 milliseconds
Time to serve ten page faults = 100*10 milliseconds = 1000 milliseconds = 10^6 Microseconds
Number of instructions without any page fault = 1000 - 10 = 990
Time required to run 1000 instructions = 10 Microseconds
So, time required to run 990 instructions = (10*(990/1000)) Microseconds = 9.9 Microseconds
So, the total time required to run the program = (10^6 + 9.9) Microseconds
Answer:
The number of subproblems are given as 
while the value of T(n) to be less than S(n) is for 342.
Explanation:
The number of subproblems are given as
Asymptotic running time for Strassen’s algorithm is 
Now, when a increases, number of subproblems determines the asymptotic running time of the problem and case 1 of master theorem applies. So, in worst case, asymptotic running time of the algorithm will be
Now, for T(n) to be smaller than S(n)
So,
So,
a=342
