Question

Write a method called removeInRange that accepts four parameters: an ArrayList of integers, an element value, a starting index, and an ending index. The method's behavior is to remove all occurrences of the given element that appear in the list between the starting index (inclusive) and the ending index (exclusive). Other values and occurrences of the given value that appear outside the given index range are not affected. For example, for the list [0, 0, 2, 0, 4, 0, 6, 0, 8, 0, 10, 0, 12, 0, 14, 0, 16], a call of removeInRange(list, 0, 5, 13); should produce the list [0, 0, 2, 0, 4, 6, 8, 10, 12, 0, 14, 0, 16]. Notice that the zeros located at indices betwee

Answer 1

Answer:

public static void removeInRange(List<Integer> list, int value, int start, int end) {

       for (int i = end - 1; i >= start; i--) {

           if (list.get(i) == value) {

               list.remove(i);

           }

       }

       System.out.println(list);

   }

Explanation:

- Create a method named removeInRange that takes four parameters, a list, an integer number, a starting index and an ending index

- Inside the method, initialize a for loop that iterates between starting index and ending index

- If any number between these ranges is equal to the given value, then remove that value from the list, using remove method

- When the loop is done, print the new list