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mina [271]
3 years ago
7

A survey of Mrs. Ramirez's students showed that 30

Mathematics
1 answer:
Umnica [9.8K]3 years ago
3 0

Answer: 480

Step-by-step explanation:

We can create a ratio for this!

We have:

\frac{number of hamburgers}{total students}= \frac{new number of hamburgers}{new number of students}

We can use substitution to input the information we already know:

\frac{12}{30} = \frac{x}{1200}

Using cross multiplication, we get:

1 200(12) = 30x

14,400 = 30x

\frac{14,400}{30}=\frac{30x}{30}

x = 480

Hope this helps! :)

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Answer:

  • A)40 I hope the answer is correct . I will be happy when I get 5 point
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2. The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4.5. Suppose we going t
stiv31 [10]

Answer:

P(\bar X>76)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 76 we got:

z =\frac{76-75}{\frac{4.5}{\sqrt{81}}}= 2

And if we use the complement rule and the normal standard distribution or excel we got:

P(Z>2) = 1-P(Z

And we can find this using the ti 84 with the following code:

1-normalcdf(-1000, 76, 75, 0.5 )

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable who represent the score of golfers. We select a sampel size of 81.

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X>76)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 76 we got:

z =\frac{76-75}{\frac{4.5}{\sqrt{81}}}= 2

And if we use the complement rule and the normal standard distribution or excel we got:

P(Z>2) = 1-P(Z

And we can find this using the ti 84 with the following code:

1-normalcdf(-1000, 76, 75, 0.5 )

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3 years ago
Which sequences of transformations confirm the congruence of shape II and shape I?
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The answer is -1 and 12
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Mark simplified 3/5 divided by 5/8; his work is shown below. Identist where he made his error.
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Answer:

Mark forgot to multiply 5 · 5, so he ended up with 5 in the denominator instead of 5 · 5 = 25

Step-by-step explanation:

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A businessman is required to collect a 5% sales tax. One day he collected $281 in taxes. Find the total amount of sales he made
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I don't fully understand the question but I hope this helps...

I believe this would mean he made $1405 that day.
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