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anzhelika [568]
2 years ago
11

Karan and Preeti are sharing a packet of sweets in the ratio of 2:3 .If the total sweets is 50,how many sweets will Preeti get

Mathematics
1 answer:
Viktor [21]2 years ago
8 0

Answer:

30 sweets

Step-by-step explanation:

From the above question

The ratio is given as:

Karan : Preeti

2:3

The sum of the proportion = 2 + 3 = 5

Total number of sweets = 50 sweets

The number of sweets Preeti will get is calculated as:

3/5 × 50 sweets

= 30 Sweets

Therefore, the number of sweets Preeti will get is 30 sweets

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The second quartile is also the median. which is 50% of the data. So 1/2 of the data lies below it, and 1/2 of the data lies above it.
the correct answer would be A. the data value of 2.5 will lie below the second quartile.
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Which equation is a function of x?
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In a chess variant, a "lord" can move one space at a time, either upward, or to the right, or diagonally up and to the right. ho
valentina_108 [34]

There are 48639 ways for a lord to move from the bottom left to top right corner of the 8 by 8 chessboard

<h3>Further explanation</h3>

The probability of an event is defined as the possibility of an event occurring against sample space.

\large { \boxed {P(A) = \frac{\text{Number of Favorable Outcomes to A}}{\text {Total Number of Outcomes}} } }

<h2>Permutation ( Arrangement )</h2>

Permutation is the number of ways to arrange objects.

\large {\boxed {^nP_r = \frac{n!}{(n - r)!} } }

<h2>Combination ( Selection )</h2>

Combination is the number of ways to select objects.

\large {\boxed {^nC_r = \frac{n!}{r! (n - r)!} } }

Let us tackle the problem.

This problem is similar to Pascal Triangle.

The Lord can move to the right or up in one way only.

We can put "1" in each box on the bottom and left to represent 1 possible movement.

To get the possibility of movement to another box, we will add the possibility of movement to the left, right, and diagonal squares as shown in Figure 1.

This process is repeated for the next box as shown in Figure 2.

Finally, after this process is repeated until the top right box, we get the results as shown in Figure 3.

There are 48639 ways for a lord to move from the bottom left to top right corner of the 8 by 8 chessboard.

<h3>Learn more</h3>
  • Different Birthdays : brainly.com/question/7567074
  • Dependent or Independent Events : brainly.com/question/12029535
  • Mutually exclusive : brainly.com/question/3464581

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Probability

Keywords: Probability , Sample , Space , Six , Dice , Die , Binomial , Distribution , Mean , Variance , Standard Deviation

7 0
3 years ago
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Answer:

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Keep the denumerator the same and subtract the numerators.

2/4

Then simplify

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4 0
2 years ago
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