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True [87]
3 years ago
13

a baseball diamond is a 90ft square. the mound is 60.5 ft from home plate. how far is it from the mound to first base.

Mathematics
1 answer:
vodka [1.7K]3 years ago
3 0
X=63.7 Feet
Hope this helps.
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AB lies on a number line. The coordinate of point A is -6. Given that AB=20, what are two possible coordinates for point B?
Dafna1 [17]

Answer:

<em>-26 or 14</em>

Step-by-step explanation:

Given that

Coordinate of point A is -6.

Length of AB = 20

To find:

Coordinates for the point B = ?

Solution:

We are given that:

AB = 20

In other words, we can use modulus function to define the distance between A and B:

|Coordinates of B - Coordinates of A| = 20

Let the coordinates of B = x

Kindly refer to the attached image for the given situation.

Point B might be either on the left or on the right side of A.

That means:

|x-(-6)| = 20\\\Rightarrow |x+6|=20

Now, let us have a look at the modulus function:

|y|=\left \{ {-{y}\ if\ y0} \right.

So,

|x+6|=\left \{ {-{(x+6)}\ if\ (x+6)0} \right.

(x+6 ) =20\\\Rightarrow x =14

-(x+6 ) =20\\\Rightarrow x =-26

Therefore, the answer is:

<em>-26 or 14</em>

4 0
3 years ago
ABCD is a trapezium.
lisabon 2012 [21]

The length of BC is 4.674 m

<u>Explanation:</u>

Given:

Angle A = angle B = 90°

AD = 2.1 m

AB = 1.9 m

CD= 3.2 m

An image is inserted for the reference

According to the figure,

a is the base

b is the height

c is the hypotenuse

Using pythagoras theorm:

a² + b² = c²

a² + (1.9)² = (3.2)²

a² + 3.61 = 10.24

a² = 6.63

a = 2.574

BC = 2.1 + 2.574

BC = 4.674m

Therefore, the length of BC is 4.674 m

7 0
3 years ago
The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
Slope is –2 &amp; (5, 3) is on the line.<br> Y-Intercept:<br> Equation of the line (no spaces):
GREYUIT [131]

Answer:

The y intercept is (0,13)

The equation of the line is y = -2x+13

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b  where m is the slope and b is the y intercept

y = -2x+b

Substituting the point

3 = -2(5) +b

3 = -10 +b

Add 10 to each side

13 =b

The y intercept is (0,13)

The equation of the line is y = -2x+13

5 0
3 years ago
Is there anyone who is expert in maths ?I’m in grade 9 can someone help me with maths pls tomorrow is my exam :(
sammy [17]

Answer:

Expert? Sorry, not me, but what sort of questions do you have?

Step-by-step explanation:

7 0
2 years ago
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