Is that i see you everywhere you go
Answer: 54.17
Step-by-step explanation:
Basically, what this asks you is to maximize the are A=ab where a and b are the sides of the recatangular area (b is the long side opposite to the river, a is the short side that also is the common fence of both corrals). Your maximization is constrained by the length of the fence, so you have to maximize subject to 3a+b=450 (drawing a sketch helps - again, b is the longer side opposite to the river, a are the three smaller parts restricting the corrals)
3a+b = 450
b = 450 - 3a
so the maximization max(ab) becomes
max(a(450-3a)=max(450a-3a^2)
Since this is in one variable, we can just take the derivative and set it equal to zero:
450-6a=0
6a=450
a=75
Plugging back into b=450-3a yields
b=450-3*75
b=450-225
b=215
Hope that helps!
it would have to be the first one y=x+2
Answer:
55
Step-by-step explanation:
The first crayon is chosen out of 11,so there are 11 choices
11
The second crayon is chosen out of 10 crayons left so there are 10 choices
10
11*10 = 110
But we do not care about the order, so we divide by 2 since there are 2 places
110/2 =55
