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Marta_Voda [28]
3 years ago
15

Ms. Yung bought 18.5 pounds of candy to make treat bags for Halloween. If she plans on putting 0.2 pounds of candy in each bag,

how many treat bags can she make?
Mathematics
1 answer:
laiz [17]3 years ago
7 0

Answer:

92 treat bags

Step-by-step explanation:

In order to calculate the total amount of treat bags that Ms. Yung can make we would simply need to divide the weight of each bag's candy by the total weight of candy that Ms. Yung has. This would evenly divide the total amount of candy into as many bags as possible.

18.5 lbs. / 0.2lbs = 92.5 bags

Therefore, if we divide evenly Ms. Yung would be able to make a total of 92 treat bags because even though she has for half a bag left it would not be an entire treat bag like she wants.

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\begin{aligned}P(A \cup B) & \Rightarrow \text { Person taking either taxi/subway } \\&=P(A)+P(B)-P(A \cap B) \\&=(0.85-0.555)+(0.6-0.55)-0.55 \\&=1.45-0.55\\&\bf{=0.9} \end{aligned}

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Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park: A coordinate plane is shown.
Nostrana [21]

Question:

Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park.There is a point at (−6, 3) labeled Dog 1. There is a point at (−6, −3) labeled Dog 2.

Which statement best describes the relationship between the positions of the two players?

A.Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

B.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

C.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.

D. Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.

Answer:

Option B: Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

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The position of the Dog 1 is (−6, 3).

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