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2 years ago

M<2=4x+12 Someone help

Mathematics

2 answers:

Katarina [22]2 years ago

8 0

X=12. So this one says that it has 3 congruent sides so therefore it has to have 3 congruent angles. Here we have angle 2 and we have angle 60. Given the definition of triangle congruence, we can say that 60 is angle 2 and that the third angle is also 60 but it’s not relevant in this problem. So knowing that angle 2 is 4x+12 we solve for x by seeding that equal to 60 and then solving for x we get x=12. Hope this helps!!!!

Volgvan2 years ago

8 0

Answer: m∠2 =60

60=4x+12

subtract 12 from both sides

60-12=4x+12-12

60-12=4x

48=4x

divide both sides by 4

48÷4=4x÷4

48÷4=x

x=12

Plug it into the equation

4(12)+12=

48+12=

m∠2 =60

another proof is that they are congruent

I hope this is good enough:

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3 years ago

Y=-×+1 and y=2×+4 how many solutions when graphed

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One solution (-1,2)

Step-by-step explanation:

Since these two linear equations have different slopes, different y-intercepts, and are indeed linear, these equations will only have one crossing when graphed, and hence one solution.

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3 years ago

The height of a triangle is 3cm less than twice the base. The area is 10cm2

Kamila [148]

Answer:

The base is 4cm and the height is 5cm.

Step-by-step explanation:

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Sub the first equation into the second (as H is already isolated). You will end up with a quadratic equation - solve that any way you wish (e.g. quadratic formula). I've provided the factored form below which shows you the roots:

$\frac{B(2B-3)}{2}=10\\\frac{2B^2-3B}{2}=10\\2B^2-3B=20\\2B^2-3B-20=0\\(2B+5)(B-4)=0\\B= - \frac{5}{2},4$

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$H=2(4)-3\\H=8-3\\H=5$