Answer:
Questions involving accelerating objects, including those in free fall, can be solved using three equations
y = 1/2at2 + v0t + y0
v = v0 + at
vf2 = v02 + 2 a (y - y0)
In this case, only the first equation is needed.
Since the object is falling the final height is 0 meters, the initial height is 370 m, and the acceleration is -9.8ms-2
Since the object is dropped, the initial velocity is 0.
0 = 1/2(-9.8)t2 + 370. t = sqrt(370/4.9) = 8.69 s
Explanation:
Infared = used by police
gamma = short wavelength
radio = largest wavelength
visible = only ones we can see
That's what I call my "weight".
