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Phantasy [73]
3 years ago
15

Which of the following is not a unit of torque? O pound-foot 0 kilogram-newton Newton-meter O pound-inch

Physics
1 answer:
VladimirAG [237]3 years ago
6 0

Answer: Kilogram- newton is wrong unit for Torque

Idem pound-inch is also wrong unit for Torque

Explanation: As it is well known the torque is defined as :

Τorque= F x R

so its UNITS are Newton*meter (SI)

or in the Imperial System is often use  Pound-foot

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A 5kg wheel rolls off a flat roof of a 50 m tall building at 12m/s.
Olegator [25]

Explanation:

a) Given in the y direction (taking down to be positive):

Δy = 50 m

v₀ = 0 m/s

a = 10 m/s²

Find: t

Δy = v₀ t + ½ at²

50 m = (0 m/s) t + ½ (10 m/s²) t²

t = 3.2 s

b) Given in the x direction:

v₀ = 12 m/s

a = 0 m/s²

t = 3.2 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (12 m/s) (3.2 s) + ½ (0 m/s²) (3.2 s)²

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6 0
3 years ago
6. An excited dog runs full-speed toward his owner who has just returned home from
mixas84 [53]

Answer:

v = 8.65 m/s

Explanation:

Given that,

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v=\dfrac{45\ m}{5.2\ s}\\\\=8.65\ m/s

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4 0
3 years ago
What are the average velocity and average acceleration of the tip of a 2.4 cm long hour hand of a clock?
ra1l [238]
A circle has a revolution of 360°. Since there are 12 hour markings, each hour interval has an angle of 30°. In radians, that would be equal to π/6 radians. So, in every 1 hour that passes, it covers π/6 of an angle. So, the angular velocity denoted as ω is π/6 ÷ 1 hour = π/6 rad/h. We can compute the average linear velocity, v, from the relationship:

v = rω, where r is the radius of the circle which is the length of the hour hand
v = (2.4 cm)(π/6 rad/h)
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Therefore, the average velocity is 1.257 cm per hour.

For the average acceleration, it is equal to zero. The hands of the clock move at a constant velocity. Since acceleration is the change of velocity per unit time, there is no change of velocity because it's constant. That's why it is zero.

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