Answer:
1) Area = 12cm²
2) x = 5cm
Surface area : 69cm²
Step-by-step explanation:
Opposites sides in a rectangle would equal the same.
so Top/bottom = 20+20=40
Front/back = 15+15=30
40+30=70cm²
94-70=24cm² for left and right side 24÷2=12cm²
2) Those lines represents what side it is equal too which also means the same.
3cm, you know that base x height = surface area so surface area ÷ height = base
15/3=5cm
x=5cm
Formula : Base x Height = One surface area
Front/Back= 15+15=30
Top/bottom = 5x3 = 15+15=30
side/side = 3x3=9
30+30+9=69cm²
Answer:
A,B, C are right!
Step-by-step explanation:
If you were to plot those numbers on the line, it would be true!
Good Luck!!!!!
Step-by-step explanation:
The problem statement says λ<1. If this is true, then the cannonball is slower than the boat, and it will never reach the boat. So I assume it's actually λ>1.
If we say t is the amount of time, then the boat travels south a distance of ut, and the cannonball travels a distance of λut.
v = λut
ut = v/λ
Using Pythagorean theorem:
d² + (ut)² > v²
d² + (v/λ)² > v²
λ²d² + v² > λ²v²
λ²d² > (λ² − 1) v²
λ² / (λ² − 1) > (v/d)²
Answer:
See below
Step-by-step explanation:
m=y2-y1/x2-x1
Coordinate 1 - (2, 140)
Coordinate 2 - (4, 280)
280-140/4-2
140/2 = 70
y=70x
Answer:
Scale factor = 2 for C
Scale factor = 2 for D
Scale factor = 2 for B
Step-by-step explanation:
Shape C has the dimensions of 2 x 6
Shape A has the dimensions of 1 x 3
Shape C is exactly 2 times an englargement of A because:
multiply 1 (dimension of A) times 2 (scale factors) = 2 (dimension of C)
multiply 3 (dimension of A) times 2 (scale factors) = 6 (dimension of C)
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Shape D has the dimensions of 2 x 6
Shape A has the demensions of 1 x 3
Shape D is exactly 2 times an englargement of A because (same as C):
multiply 1 (dimension of A) times 2 (scale factors) = 2 (dimension of D)
multiply 3 (dimension of A) times 2 (scale factors) = 6 (dimension of D)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Shape B has the dimensions of 3 x 9
Shape A has the demensions of 1 x 3
Shape B is exactly 3 times an englargement of A because:
multiply 1 (dimension of A) times 3 (scale factors) = 3 (dimension of B)
multiply 3 (dimension of A) times 3 (scale factors) = 9 (dimension of B)
