1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
meriva
3 years ago
10

True or false? Three out of two people have trouble with fractions. Please explain

Mathematics
1 answer:
svetlana [45]3 years ago
8 0

Answer:

False

Step-by-step explanation:

3 out of 2 can be represented as 3/2 which simplified is 1.5, This statement is saying that out of 1 person, 1.5 of them have trouble with fractions which isn't possible because 2/2 is the whole amount, so anything above 2/2 is simply not possible <u>in this scenario</u>

You might be interested in
Find the area PLEASE ASAP HELPPPPPPPPP
Luda [366]

Answer:

18

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Mr. Niles used 5/12 of a carton of eggs to make breakfast Saturday. He used 2/12 of the carton on Sunday. How many more eggs did
Alla [95]

Answer:

hey guys this is my other account

Step-by-step explanation:

6 0
3 years ago
Count the number of 5-digit numbers (in the decimal system; integers from 10000 to 99999) which are not divisible by 11.
Alexxandr [17]

Answer:

So total number which is not divisible by 11 = 89999-8181 = 81819  

Step-by-step explanation:

We have to find the total numbers which are not divisible by 11 from 10000 to 99999

Total number from 10000 to 99999 = 99999-10000+1=90000

Just after 10000 the number which is divisible by 11 is 10010

And just below 99999 the number which is divisible by 11 is 99990

Using AP formula

T_N=a+(n-1)d, here a is first term, d is common difference and n is number of terms

So 99990=10010+(n-1)11

n-1 = 8180

n= 8181

So total number which is not divisible by 11 = 90000-8181 = 81819

4 0
3 years ago
A well mixed tank with a capacity of 1500 gals originally contains 1000 gallons of freshwater. One pipe containing 1/2 lb of sal
Illusion [34]

Answer:

400 lb of salt

Step-by-step explanation:

Let us assume the water flows into the rank for x minutes.

There is an initial of 1000 gallons of water in the tank and water flows in through one pipe at 4 gal/min and through another pipe at 6 gal/min. In x minute, the amount of water in the tank = 1000 + 4x + 6x = 1000 + 10x

Water flows out at 5 gal/min, therefore in x minute the amount of water in the tank = 1000 + 10x - 5x = 1000 + 5x

The tank begins to overflow when it is full (has reached 1500 gallons). Therefore:

1500 = 1000 + 5x

5x = 1500 - 1000

5x = 500

x = 100 minutes.

1/2 lb salt per gallon flows into the tank at 4 gal/min and 1/3 lb of salt is flowing in at 6 gal/min, in 100 min the amount of salt that entered the tank = 4 gal/min × 100 min × 1/2 lb/gal + 6 gal/min × 100 min × 1/3 lb/gal= 400 lb

Therefore the amount of salt is in the tank when it is about to overflow = 400 lb of salt

7 0
3 years ago
Use compatible numbers to estimate the quotient of 776÷28
kiruha [24]
The answer to ur division problem would be 27.6785714286<span>
</span>
4 0
3 years ago
Other questions:
  • –4y=10 in standard form
    13·2 answers
  • What is 8 times 5/6​
    6·1 answer
  • The original price is 125 dollars and sale price is 81.25 dollars what is the discount
    15·1 answer
  • Question 3 (1 point)
    11·1 answer
  • Emmanuel collected 49 Leaves last week he collected the same number of leaves each day how many leaves did he collect on Monday
    13·2 answers
  • Math help! 20 points and brainiest answer
    6·2 answers
  • 2. A certain TV can be purchased from the manufacturer for $160. A certain online retailer has a standard markup of 30%, and a c
    13·1 answer
  • 5y-14=2y-2 solve for y and show work plz
    12·2 answers
  • What is the value of x?
    14·2 answers
  • Given that the measure of angle 3 is 75o. What is the value of x if the measure of angle 7 is (x + 40) ?
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!