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IRISSAK [1]
3 years ago
6

Let n represent the time in hours for the service call and C represents the total cost in dollars. Write an equation that relate

s C and n
Mathematics
1 answer:
USPshnik [31]3 years ago
8 0

Answer:

C(n) = pn

Step-by-step explanation:

Given :

n = time in hours for service call

C = total cost

Total cost = unit cost per hour * time in hours

If unit cost per hour = p

Hence,

C(n) = p * n

C(n) = pn

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Is it possible to find another line that’s parallel to 3x+9y=1 and passes through (0, 1/9)
LuckyWell [14K]

Answer:

no it is not

Step-by-step explanation:

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9y=-3x+1

y=-1/3x+1/9

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6 0
3 years ago
My Notes A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1600 hours and
Evgen [1.6K]

Answer:

The bulbs should be replaced each 1436.9 hours.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1600, \sigma = 70

How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?

This is the first percentile of hours. So it is X when Z has a pvalue of 0.01.

So it is X when Z = -2.33.

Z = \frac{X - \mu}{\sigma}

-2.33 = \frac{X - 1600}{70}

X - 1600 = -2.33*70

X = 1436.9

The bulbs should be replaced each 1436.9 hours.

6 0
3 years ago
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