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Answer:
B
Step-by-step explanation:
Answer:
The observed tumor counts for the two populations of mice are:
Type A mice = 10 * 12 = 120 counts
Type B mice = 13 * 12 = 156 counts
Step-by-step explanation:
Since type B mice are related to type A mice and given that type A mice have tumor counts that are approximately Poisson-distributed with a mean of 12, we can then assume that the mean of type A mice tumor count rate is equal to the mean of type B mice tumor count rate.
This is because the Poisson distribution can be used to approximate the the mean and variance of unknown data (type B mice count rate) using known data (type A mice tumor count rate). And the Poisson distribution gives the probability of an occurrence within a specified time interval.
Answer:
15 2/3, or 47/3
Step-by-step explanation:
I'm going to assume, correctly or not, that you actually meant f(x) = 2x^2 - (1/3)x + 5. Double check on this right now, please.
If I'm right, then evaluate f(x) at x = 0 and x = 8:
f(0) = 5
and
f(8) = 2(8)^2 - (1/3)(8) + 5 = 128 - 8/3 + 5 = 133 - (2 2/3), or: 130 1/3
Then the average rate of change of f(x) = 2x^2 - (1/3)x + 5 over the interval [0,8] is:
130 1/3 - 5 125 1/3
a. r. c. = ------------------- = ---------------- = 15 2/3, or 47/3
8 - 0 8
