Answer:
How to factor out a polynomial with a 3rd degree-• well here is a For example, let G(x) = 7x³ – 125. Then factoring this third degree polynomial relieve on a differences of cubes as follows: (2x – 5) (4x² + 20x + 25), where ²x is the cube-root of 8x³ and 5 is the cube-root of 1256
Answer:
y=5 when x=20
Step-by-step explanation:
Using the format for inverse proportions: y=k/x
To find k, substitute 25 in for y and 4 for x to find:
25=k/4 ⇒ k=100
Using this we can substitute k and x in for 100 and 20 to find:
y=100/20 ⇒ y=5
The equation seems to be
1
-------- = 5 ^ (x + 4)
25
In that case, this is the solution, stept by step:
1) factor 25: 25 = 5^2
1
=> ----------- = 5^(x + 4)
5^2
2) invert 5^2
=> 5^(-2) = 5^(x+4)
3) Given that the bases are equal, the exponents also have to be equal:
=> - 2 = x + 4
3) transpose +4:
=> - 2 - 4 = x
=> x = - 6
Answer: - 6
Choose the 5th box, then the answer is 720in
