The answer is D because the layers all the way at the bottom had to be there for other layers to be built on top
Exactly 989527/1048576, or approximately 94.37%
Since each trait is carried on a different chromosome, the two traits are independent of each other. Since both parents are heterozygous for the trait, each parent can contribute 1 of a possible 4 combinations of the alleles. So there are 16 possible offspring. I'll use "a", "A", "b", "B" to represent each allele and the possible children are aabb, aabB, aaBb, aaBB, aAbb, aAbB, aABb, aABB, Aabb, AabB, AaBb, AaBB, AAbb, AAbB, AABb, and AABB
Of the above 16 possibilities, there are 7 that are homozygous in an undesired traint and 9 that don't exhibit the undesired trait. So let's first calculate the probability of "what are the chances that all 5 children not exhibiting an undesired trait?" and then subtract that result from 1. So
1-(9/16)^5 = 1 - 59049/1048576 = 989527/1048576 which is approximately 0.943686485 = 94.3686485%
So the answer is exactly 989527/1048576, or approximately 94.37%
Is kinda blurry can u take a better picture
Since there are 20 heigh-associated genes and only two of the alleles are identical to both of them, the other genes could have different effects on the development of their bone and muscle cells which can result to the two women having different heights.
