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aivan3 [116]
2 years ago
9

I need help what is 3^{-2}

Mathematics
1 answer:
blagie [28]2 years ago
5 0

Answer:

0.1

Step-by-step explanation:

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Write one-half times a number minus 4. use x as a variable
alexdok [17]

Answer:

\frac{1}{2}x-4

Step-by-step explanation:

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Please help ill give brainliest!! Im terrible at math :(<br><br> What is: 3 divided by \frac{1}{4} ?
Ghella [55]

Answer:

12

Step-by-step explanation:

3 ÷ 1/4

Copy dot flip

Keep the first number, change the divide to multiply and take the reciprocal of the 2nd number

3 * 4/1

12

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13 boxes can I get brainliest please ❤️
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Two corresponding sides of similar triangles are 2 cm and 5 cm. What is the area of the second triangle if the area of the first
Stella [2.4K]

Answer:

(1) Area of second triangle= 50 cm^2.

(2) Area of ΔABC=98 cm^2.

   and Area of ΔDFG=175 cm^2.

Step-by-step explanation:

<em>" For two similar triangles the ratio of sides is equal to the ratio of square of their areas".</em>

i.e. if a,b are the corresponding sides of two similar triangles and let A and B denote the area of two triangles then we have the relation as:

\dfrac{a^2}{b^2}=\dfrac{A}{B}

(1)

for the first question:

we have a=2, b=5.

A=8 cm^2.

Hence,

\dfrac{2^2}{5^2}=\dfrac{8}{B}\\\\\dfrac{4}{25}=\dfrac{8}{B}

B=50 cm^2.

Hence, the area of second triangle is 50 cm^2.

(2)

In second option we have:

a=6 and b=5.

A-B=77 cm^2.

A=77+B

\dfrac{6^2}{5^2}=\dfrac{A}{B}\\  \\\dfrac{36}{25}=\dfrac{77+B}{B}\\  \\36B=25\times77+25B\\\\36B-25B=25\times77\\\\11B=25\times77\\\\B=25\times7\\\\B=175

Hence area of second triangle i.e. ΔDFG is 175 cm^2.

and area of first triangle i.e. ΔABC=175-77=98 cm^2.




8 0
2 years ago
+{-x2y+[-(x2y-2xy2+y2)+(-xy2-3y2+x2y)]-(10y2-x2y)}
Kay [80]

Answer:

3xy² -  14y²      

Step-by-step explanation:

I hope that this is the problem

   - x²y + [ - (x²y - 2xy² + y²) + (xy² - 3y² + x²y)] - (10y² - x²y)

= - x²y + [ - x²y + 2xy² - y² + xy² - 3y² + x²y] - 10y² + x²y

Now combine like terms in the [  ].

= - x²y  + [ -x²y + x²y + 2xy² + xy² - y² - 3y² ] - 10y² + x²y

= - x²y  + [ 0 + 3xy² - 4y²] - 10y² + x²y

= - x²y + 3xy² - 4y² -10y² + x²y                      Now combine like terms

=   (-x²y + x²y) + 3xy² + (-4y² - 10y²)

=       0 + 3xy² - 14y²

=  3xy² -  14y²       or    y²(3x - 14)

6 0
2 years ago
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