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3 years ago

Use long division to find the value of 1875 ÷ 15 THIS IS A DIVISON PROBLEM SINCE THE OTHER ONE I WROTE A MULTIPLICATION PROBLEM

Mathematics

1 answer:

Arisa [49]3 years ago

6 0

The answer to 1875/15 is 125 with no remainder!

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While playing a game, you move 5 steps forward and then 11 steps backward. Write each number as an integer

MaRussiya [10]

To represent 5 steps forward as an integer, you would write 5 or +5. Forward is a positive movement.

11 steps backward would be -11 because moving backwards would be the opposite of moving forward (+).

7 0

3 years ago

What is the correct classification of the square root of 18

klio [65]

I would say irrational. Hope this helps!

8 0

3 years ago

Read 2 more answers

Let A={2,3,4} B={2,5,6} C={5,6,2} and D={6}. Determine if the following statements are true:

Pie

Answer:

i. 4∈C => False

ii. 5∈C => True

iii. A = B => False

iv. B=C => True

Step-by-step explanation:

Given sets are:

$A = \{2,3,4\}\\B = \{2,5,6\}\\C = \{5,6,2\}\\D = \{6\}$

Lets look at the statements one by one.

i. 4∈C

This statement means that 4 is a member of set C. Looking at the members of set C, it can be concluded that the statement is wrong as C doesn't contain 4.

ii. 5∈C

This statement is true as 5 is a member of C.

iii. A=B

This statement states that set A is equal to set B. Two sets are said to be equal if there number of elements and members are same. Set A and Set B have different members so this statement is false.

iv. B=C

Set B and Set C have equal number of members and the members (5,6,2) are also same so the statement is true.

Hence,

i. 4∈C => False

ii. 5∈C => True

iii. A = B => False

iv. B=C => True

5 0

3 years ago

Let A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, and C = {5, 6, 7, 8}. Find each of the following sets. (Enter your answers in set-roster

cluponka [151]

Answer:

(a) {1, 2, 5, 6}

(b) {3, 4, 7, 8}

(c) {1, 2, 3, 4, 5, 6, 7, 8}

(d) {1, 2, 7, 8}

Step-by-step explanation:

Given sets,

A = {1, 2, 3, 4}, B = {3, 4, 5, 6} and C = {5, 6, 7, 8},

(a) Since, A Δ B = (A\B)∪(B\A) = all elements of A\B and B\A

∵ A\B = elements of set A which are not in B

= {1, 2}

And, B\A = {5, 6}

So, A Δ B = {1, 2, 5, 6}

(b) B\C = {3, 4},

C\B = {7, 8}

⇒ B Δ C = (B\C)∪(C\B) = {3, 4, 7, 8}

(c) A\C = {1, 2, 3, 4},

C\A = {5, 6, 7, 8},

⇒ A Δ C = (A\C)∪(C\A) = {1, 2, 3, 4, 5, 6, 7, 8}

(d) (A Δ B)\C = {1, 2}

C\(A Δ B) = {7, 8}

A Δ C = ((A Δ B)\C)∪(C\(A Δ B)) = {1, 2, 7, 8}

7 0

3 years ago

Helppp theseee It would be great☺️

iren2701 [21]

4=4.

I hope helped ^-^

5 0

3 years ago

Read 2 more answers

Use long division to find the value of 1875 ÷ 15 THIS IS A DIVISON PROBLEM SINCE THE OTHER ONE I WROTE A MULTIPLICATION PROBLEM​

Use long division to find the value of 1875 ÷ 15 THIS IS A DIVISON PROBLEM SINCE THE OTHER ONE I WROTE A MULTIPLICATION PROBLEM