Answer:
20 longs, 9 units more than the 9 flats
Step-by-step explanation:
If Abby has 9 flats, she has 900 blocks of the 1109 she needs. The remaining 209 can be represented by ...
20 longs
9 units
_____
<em>Comment on the question</em>
We cannot see the model Abby has put together so far, so we don't know exactly what it takes to finish it. Any longs or units she already shows must be subtracted from the numbers above.
Answer:
alphabet D I think ASA axiom
<span>From the message you sent me:
when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths
If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

Why does this work? Initially, you start with 500 mL of air that you breathe in, so

. After the second breath, you have 12% of the original air left in your lungs, or

. After the third breath, you have

, and so on.
You can find the amount of original air left in your lungs after

breaths by solving for

explicitly. This isn't too hard:

and so on. The pattern is such that you arrive at

and so the amount of air remaining after

breaths is

which is a very small number close to zero.</span>
Answer:
The result in standard form is: 
Step-by-step explanation:
Dividing the values:
To find the real part, we divide 2.645 by 1.15. So
2.645/1.15 = 2.3
Finding the power:
Its a division, so we keep the base, and subtract the exponents. So

Result in standard form:
The result in standard form is: 