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Papessa [141]
3 years ago
13

Use long division to find the value of 1875 ÷ 15 THIS IS A DIVISON PROBLEM SINCE THE OTHER ONE I WROTE A MULTIPLICATION PROBLEM​

Mathematics
1 answer:
Arisa [49]3 years ago
6 0
The answer to 1875/15 is 125 with no remainder!
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Abby uses base 10 blocks to show 1,109. She has no thousands cubes and only 9 flats, as shown. Draw longs and units on the chart
Vinvika [58]

Answer:

  20 longs, 9 units more than the 9 flats

Step-by-step explanation:

If Abby has 9 flats, she has 900 blocks of the 1109 she needs. The remaining 209 can be represented by ...

  20 longs

  9 units

_____

<em>Comment on the question</em>

We cannot see the model Abby has put together so far, so we don't know exactly what it takes to finish it. Any longs or units she already shows must be subtracted from the numbers above.

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3 years ago
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Lilit [14]

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5 0
2 years ago
Amy was given an amount of money, m, for good grades on her report card. She spent $15.00 and now has $25.32. How much money did
Vaselesa [24]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
Work out the value<br> of <br> 2. 4510 ×10to the power of 9<br> 1.15 × 10 to the power of 3
Simora [160]

Answer:

The result in standard form is: 2.3 \times 10^{6}

Step-by-step explanation:

Dividing the values:

To find the real part, we divide 2.645 by 1.15. So

2.645/1.15 = 2.3

Finding the power:

Its a division, so we keep the base, and subtract the exponents. So

\frac{10^9}{10^3} = 10^{9-3} = 10^{6}

Result in standard form:

The result in standard form is: 2.3 \times 10^{6}

8 0
3 years ago
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