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Stolb23 [73]
3 years ago
15

PLZ HELP!!!

Mathematics
1 answer:
likoan [24]3 years ago
6 0

Answer:

The rental fee is 25

Step-by-step explanation:

Total cost = rental fee plus cost per hours * number hours

t = f + 8*h  where t = total cost, f = rental fee, h = hours

73 = f + 8*6

73 = f+ 48

Subtract 48 from each side

73 - 48 = f+48-48

25 = f

The rental fee is 25

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f(x) has domain , and range . A 2-column table with 5 rows. Column 1 is labeled x with entries negative 4, negative 2, 0, 2, 4.
laiz [17]

Answer:

Domain: {-4, -2, 0, 2, 4}

Range: {-2, -1, 0 1, 2}

Step-by-step explanation:

5 0
3 years ago
Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl
lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13

x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88

x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63

x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38

x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13

So, the table becomes:

\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}

Next, calculate the mean

\bar x = \frac{\sum fx}{\sum f}

\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}

\bar x = \frac{1845.73}{146}

\bar x = 12.64

Next, the sample variance is:

\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}

So, we have:

\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}

\sigma^2 = \frac{2393.6875}{145}

\sigma^2 = 16.51

The sample standard deviation is:

\sigma = \sqrt{\sigma^2}

\sigma = \sqrt{16.51}

\sigma = 4.06

6 0
2 years ago
Can somebody please help me !!!!!!!!!47$4&
Andrews [41]

Answer:

30 celsius

Step-by-step explanation:

(86°F − 32) × 5/9 = 30°C

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Monica is completing an Algebra test worth 100 points. There are 14 questions on the test that are equally valued. How many poin
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What value of x is in the solution set of 8x – 6 > 12 + 2x?
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<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>!</em>

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