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2 years ago

55% of the 300 students in 6th grade have a younger brother or sister. How many 6th graders have a younger sibling?

Mathematics

2 answers:

Salsk061 [2.6K]2 years ago

7 0

Answer:

(A) 100 x 3 = 300 (B) 55 x 3 = the answer (E) 55 x 3 = 165 students (F) 165 6th graders have a younger sibling.

Step-by-step explanation:

I did the assignment and (A) (B) (E) and (F) were correct. Give the other person brainliest

hope it helps

Anna007 [38]2 years ago

6 0

Answer:

A, B, E, F.

Step-by-step explanation:

I did the assignment and got it right

100x3=300

55x3= the answer

55x3=165 students

165 6th graders have a younger sibling

Hope this helps

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Over the last 3 evenings, Keisha received a total of 81 phone calls at the call center. The first evening, she received 6 few

tensa zangetsu [6.8K]

Answer:

First: 15

Second: 21

Third: 45

Step-by-step explanation:

In order to create the equation we need to represent the evenings with an alebraic term, in thsi case we are going to represent the second evening with an X

Second evening:x

The first night she got 6 fewer calls than the second: Second-6=x-6

The third night she received 3 times the first: 3(first night)=3(x-6)

The equation is First Night plus second night plus third night equals 81.

$First+second+third=81\\x+(x-7)+3(x-6)=81\\x+x-7+3x-18=81\\5x=81+21+6\\5x=105\\x=\frac{105}{5} \\x=21$

So the first evening he received 15 calls, the second he received 21 and the third one he received 45.

8 0

2 years ago

Integration by Parts Evaluate e-2x cos(2x) dx.

kifflom [539]

Let

$I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]texIntegrate by parts:[tex]\displaystyle \int u \, dv = uv - \int v \, du$

with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \cos(2x) \, dx \implies v = \dfrac12 \sin(2x)$

Then

$\displaystyle I = \frac12 e^{-2x} \sin(2x) + \int e^{-2x} \sin(2x) \, dx + C$

Integrate by parts again, this time with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \sin(2x) \, dx \implies v = -\dfrac12 \cos(2x)$

so that

$\displaystyle I = \frac12 e^{-2x} \sin(2x) - \frac12 e^{-2x} \cos(2x) - \int e^{-2x} \cos(2x) \, dx + C\\\\ \implies I = \frac{\sin(2x)-\cos(2x)}{2e^{2x}} - I + C \\\\ \implies 2I = \frac{\sin(2x) - \cos(2x)}{2e^{2x}} + C \\\\ \implies I = \boxed{\frac{\sin(2x) - \cos(2x)}{4e^{2x}} + C}$

6 0

1 year ago

Three lightship flash simultaneously at 6 00 a.m the first lightship flashes every 12 sec the second lightship every 30 sec and

Dmitrij [34]

They will all flash their lights together at 5:00 pm

6 0

2 years ago

What is true about the figure?

wlad13 [49]

Answer:

<A = 56degrees

<B = 34degrees

<C = 56degrees

Step-by-step explanation:

From tyhe diagram, the sum of m<C and m<D is 180degrees. Hence;

<C + <D = 180

<C + 124 = 180

<C = 180 - 124

<C = 56degrees

Also;

<B + 90 + <C = 180

<B + 90 + 56 = 180

<B + 146 = 180

<B = 180 - 146

<B = 34degrees

Similarly;

<A + <B = 90

<A + 34 = 90

<A = 90 - 34

<A = 56degrees

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2 years ago

Which of these expressions are equivalent to 7 1/2

jekas [21]

Answer:

it's 7.5

Step-by-step explanation:

1/2 as a decimal is 0.5

5 0

1 year ago