Answer: 66
Step-by-step explanation:
To prove a quadrilateral<span> is a </span>parallelogram<span>, you must use one of these five ways. </span>Prove that<span> both pairs of opposite sides </span>are<span> parallel. </span>Prove that<span> both pairs of opposite sides </span>are<span> congruent.</span>Prove that<span> one pair of opposite sides is both congruent </span>and<span> parallel. </span>Prove that<span> the diagonals bisect each other.</span>
Multiply both sides by y...
(3/y)y-(6/y)y-2y
Simplify it...
(3/y)y=3
(6/y)y=6
3=6-2y
Subtract 6 from both sides...
-2y=-3
Divide both sides by -2...
y=3/2
The solution is y=3/2
9514 1404 393
Answer:
(-4√494)/13i +(6√494)/13k ≈ -6.8388i +0j +10.2585k
Step-by-step explanation:
To answer this question, you need to know two things:
1) the direction of vector v
2) the magnitude of vector u
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<u>direction of v</u>
A direction is specified by a "unit vector", one with the proper ratio of components, and a magnitude of 1. It is found from a given vector by dividing that vector by its magnitude.
The unit vector in the v direction is ...
v/|v| = (-2i +3k)/(√((-2)² +3²) = (-2i +3k)/√13
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<u>magnitude of u</u>
The magnitude of vector u is ...
|u| = √(5² +(-2)² +3²) = √38
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Then the desired vector is ...
(2|u|)(v/|v|) = 2√38(-2i+3k)/√13 = (-4√494)/13i +(6√494)/13k
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<em>Additional comment</em>
We have chosen to "rationalize the denominator" by writing √(38/13) as (√494)/13.
