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Reptile [31]
3 years ago
15

What is 12x squared - 9x + 15

Mathematics
2 answers:
Rashid [163]3 years ago
5 0
12x^2 - 9x + 15 = 3(4x^2-3x+5)


kupik [55]3 years ago
4 0
<u>12x² - 9x + 15</u>

It can be written as . . .

3 ( 4x² - 3x + 5 )

but that's just a different way to write the same thing. It doesn't
tell you anything new, until you know what number 'x' is.
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It’s D

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Which is the best step to do next to solve the equation by completing the square?
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Step-by-step explanation:

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3 years ago
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Select the true statement. A. Neither function is even. B. Only function f is even. C. Only function g is even. D. Both function
astraxan [27]

Answer:

The answer is "Option C".

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The graph of the even function will have both ends pointed in the same direction, while the graph of the odd function will have both ends pointed inside the reverse way. Furthermore, as the y-axis approaches, and also regular expression graph becomes symmetric. The graph of an unusual function, on either hand, is symmetric around the origin and also has rotational symmetry around the origin. They could see that the graph of function g meets a function requirement by looking at it. That graph of function f, but on the other hand, is not symmetric about its y-axis, implying that function f is not even. As both a result, g is a function that is even.

5 0
3 years ago
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42+30=[BLANK](7+5)<br> 20 POINTS!!
qaws [65]

Answer:

42+30=72

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Step-by-step explanation:

4 0
3 years ago
Use a half-angle identity to find the exact value of tan 22.5°.
dusya [7]

Answer:

\sqrt{2} -1

Step-by-step explanation:

22.5 degrees is half of 45 degrees (special angle for which we know exactly the value of all three basic trigonometric functions (sine, cosine, and tangent).

So we start recalling the formula for tangent of a half angle: tan(\frac{\alpha }{2} )= \frac{1-cos(\alpha) }{sin(\alpha) }

We need just the values of:

sin(\alpha )=sin(45^o)=\frac{\sqrt{2} }{2}

and of

cos(\alpha )=cos(45^o)=\frac{\sqrt{2} }{2}

to answer the question. Then, we use those values in the original formula for tangent of a half angle:

tan(\frac{\alpha }{2} )= \frac{1-cos(\alpha) }{sin(\alpha) }\\tan(22.5^o)=\frac{1-\frac{\sqrt{2} }{2} }{\frac{\sqrt{2} }{2}} =\frac{2-\sqrt{2} }{\sqrt{2} } =\frac{2\sqrt{2}-2 }{2} =\sqrt{2} -1

3 0
4 years ago
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